Math Problem Statement

0.5 ×AL[ (16-3-11/27.6-11) log(0.4/0.2)]×10

Solution

Let's break down and solve the given expression step by step:

0.5×AL[(1631127.611)log(0.40.2)]×100.5 \times AL \left[ (16 - 3 - \frac{11}{27.6} - 11) \log \left( \frac{0.4}{0.2} \right) \right] \times 10

Step 1: Simplify the inner expression

  1. 0.40.2=2\frac{0.4}{0.2} = 2
  2. log(2)0.3010\log(2) \approx 0.3010

Now simplify the arithmetic expression inside the parentheses:

163=1316 - 3 = 13 1127.60.3986\frac{11}{27.6} \approx 0.3986 130.398611=1.601413 - 0.3986 - 11 = 1.6014

Now the expression looks like this:

0.5×AL[1.6014×0.3010]×100.5 \times AL \left[ 1.6014 \times 0.3010 \right] \times 10

Step 2: Multiply the terms inside the brackets:

1.6014×0.30100.48201.6014 \times 0.3010 \approx 0.4820

So now we have:

0.5×AL(0.4820)×100.5 \times AL(0.4820) \times 10

Step 3: Multiply the constants:

0.5×10=50.5 \times 10 = 5

Thus, the expression becomes:

5×AL(0.4820)5 \times AL(0.4820)

Without knowing the value of ALAL, we can't compute the final result, but the simplified expression is:

5×AL(0.4820)5 \times AL(0.4820)

Let me know if you'd like more details or help with this! Here are five related questions:

  1. How does the logarithmic function behave with different bases?
  2. What is the significance of the constant AL in your equation?
  3. How do logarithmic identities simplify more complex expressions?
  4. How does precision impact the final results in calculations like this?
  5. What are common applications of logarithmic functions in physics?

Tip: Always double-check if constants or variables like ALAL are defined beforehand in specific contexts.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Logarithms
Arithmetic Simplification

Formulas

log(a/b) = log(a) - log(b)
Basic arithmetic operations: addition, subtraction, division

Theorems

Properties of logarithms
Basic algebraic manipulation

Suitable Grade Level

Grades 9-12