The formula given in the image is:

$SI = 10^{6.528 \left(\frac{1}{A} - \frac{1}{50}\right) + \log(H)}$

You provided values for $A = 30$ and $H = 70$. Let's substitute these values into the formula and calculate $SI$.

Step-by-Step Calculation:

1. Substitute $A = 30$ and $H = 70$ into the formula:

   $SI = 10^{6.528 \left(\frac{1}{30} - \frac{1}{50}\right) + \log(70)}$

2. Calculate the term inside the exponent:

   • Compute $\frac{1}{30}$ and $\frac{1}{50}$: $\frac{1}{30} = 0.0333\ldots, \quad \frac{1}{50} = 0.02$
   • Subtract $\frac{1}{50}$ from $\frac{1}{30}$: $0.0333\ldots - 0.02 = 0.0133\ldots$

3. Multiply by 6.528: $6.528 \times 0.0133\ldots = 0.0869\ldots$

4. Calculate $\log(70)$. Assuming this is the common logarithm (base 10): $\log(70) \approx 1.8451$

5. Add the two results: $0.0869\ldots + 1.8451 = 1.9320\ldots$

6. Raise 10 to the power of the result: $SI = 10^{1.9320\ldots} \approx 85.55$

Final Answer:

$SI \approx 85.55$

Would you like more details or have any questions?

Related Questions:

1. How does changing $A$ or $H$ affect the value of $SI$?
2. What is the impact of the constant 6.528 on the calculation?
3. Can we use natural logarithms instead of common logarithms in this equation?
4. How would the value of $SI$ change if $H = 100$?
5. What does the variable $SI$ represent in a real-world context?

Tip:

Always double-check which logarithm base is used in formulas to ensure accurate calculations, especially when switching between scientific and natural logarithms!