Math Problem Statement

Use the Change of Base Formula to rewrite the logarithm with the common logarithm or the natural logarithm: log3(99). Use a calculator to evaluate the logarithm. Round to four decimal places.

Solution

To solve this problem, we can use the Change of Base Formula, which states:

logb(a)=log(a)log(b)orlogb(a)=ln(a)ln(b)\log_b(a) = \frac{\log(a)}{\log(b)} \quad \text{or} \quad \log_b(a) = \frac{\ln(a)}{\ln(b)}

Here, the given logarithm is log3(99)\log_3(99). Using the formula with either common logarithms (log\log) or natural logarithms (ln\ln):

log3(99)=log(99)log(3)orlog3(99)=ln(99)ln(3)\log_3(99) = \frac{\log(99)}{\log(3)} \quad \text{or} \quad \log_3(99) = \frac{\ln(99)}{\ln(3)}

Now, let’s calculate this step by step:

Using a Calculator:

  1. Compute log(99)\log(99) and log(3)\log(3):

    • log(99)1.9956\log(99) \approx 1.9956
    • log(3)0.4771\log(3) \approx 0.4771
  2. Compute the division: log3(99)=1.99560.47714.1832\log_3(99) = \frac{1.9956}{0.4771} \approx 4.1832

Final Answer:

4.1832\boxed{4.1832}

If you want to double-check using ln\ln, the result will be the same.

Would you like a further breakdown or more details? Here are some related questions:

  1. How does the change of base formula work conceptually?
  2. Can this method be used with other bases, such as base ee?
  3. How would we rewrite and calculate log5(625)\log_5(625)?
  4. What are the practical applications of logarithms in real-life scenarios?
  5. Can you explain the difference between log\log and ln\ln?

Tip: Always double-check calculator values and round intermediate results to ensure precision in the final answer!

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Math Problem Analysis

Mathematical Concepts

Logarithms
Change of Base Formula

Formulas

log_b(a) = log(a)/log(b)
log_b(a) = ln(a)/ln(b)

Theorems

Change of Base Theorem

Suitable Grade Level

Grades 9-12