The change of base formula is:

$\log_b(a) = \frac{\log(a)}{\log(b)} \quad \text{or} \quad \log_b(a) = \frac{\ln(a)}{\ln(b)}$

Using $\log_3(80)$, we calculate:

$\log_3(80) = \frac{\log(80)}{\log(3)}$

Using a calculator:

$\log(80) \approx 1.9031 \quad \text{and} \quad \log(3) \approx 0.4771$

$\log_3(80) = \frac{1.9031}{0.4771} \approx 3.9893$

Thus, $\log_3(80) \approx 3.9893$.