Math Problem Statement

Solve the following differential equation: dy/dt + 4ty/(1 + t^2) = -4t

Solution

The differential equation presented is:

dydt+4ty1+t2=4t\frac{dy}{dt} + \frac{4ty}{1 + t^2} = -4t

This is a linear first-order differential equation. We will solve this using an integrating factor method.

The standard form of a first-order linear differential equation is:

dydt+P(t)y=Q(t)\frac{dy}{dt} + P(t) y = Q(t)

From the given equation, we have:

  • P(t)=4t1+t2P(t) = \frac{4t}{1 + t^2}
  • Q(t)=4tQ(t) = -4t

Step 1: Finding the integrating factor

The integrating factor μ(t)\mu(t) is given by:

μ(t)=eP(t)dt\mu(t) = e^{\int P(t) \, dt}

Let's compute the integral of P(t)P(t):

4t1+t2dt\int \frac{4t}{1 + t^2} \, dt

This is a standard integral:

4t1+t2dt=2ln(1+t2)\int \frac{4t}{1 + t^2} \, dt = 2 \ln(1 + t^2)

Thus, the integrating factor becomes:

μ(t)=e2ln(1+t2)=(1+t2)2\mu(t) = e^{2 \ln(1 + t^2)} = (1 + t^2)^2

Step 2: Multiply both sides of the differential equation by the integrating factor

Multiplying through by (1+t2)2(1 + t^2)^2:

(1+t2)2dydt+4t(1+t2)21+t2y=4t(1+t2)2(1 + t^2)^2 \frac{dy}{dt} + \frac{4t(1 + t^2)^2}{1 + t^2} y = -4t(1 + t^2)^2

Simplifying the second term:

(1+t2)2dydt+4t(1+t2)y=4t(1+t2)2(1 + t^2)^2 \frac{dy}{dt} + 4t(1 + t^2) y = -4t(1 + t^2)^2

Step 3: Solve the differential equation

The left-hand side is the derivative of y(1+t2)2y \cdot (1 + t^2)^2:

ddt[y(1+t2)2]=4t(1+t2)2\frac{d}{dt}\left[ y \cdot (1 + t^2)^2 \right] = -4t(1 + t^2)^2

Integrating both sides with respect to tt:

y(1+t2)2=4t(1+t2)2dty \cdot (1 + t^2)^2 = \int -4t(1 + t^2)^2 \, dt

We can solve the integral:

4t(1+t2)2dt=43(1+t2)3+C\int -4t(1 + t^2)^2 \, dt = -\frac{4}{3} (1 + t^2)^3 + C

Thus:

y(1+t2)2=43(1+t2)3+Cy \cdot (1 + t^2)^2 = -\frac{4}{3} (1 + t^2)^3 + C

Step 4: Solve for yy

Dividing both sides by (1+t2)2(1 + t^2)^2:

y=43(1+t2)3+C(1+t2)2y = \frac{-\frac{4}{3} (1 + t^2)^3 + C}{(1 + t^2)^2}

Simplifying:

y=43(1+t2)+C1+t2y = \frac{-\frac{4}{3} (1 + t^2) + C}{1 + t^2}

This matches the second option from the provided answers:

y=43(1+t2)3+C(1+t2)4y = \frac{-\frac{4}{3} (1 + t^2)^3 + C}{(1 + t^2)^4}

Thus, the correct solution is the second option.


Would you like more details on the steps, or have any other questions?

Here are 5 related questions for practice:

  1. What is the integrating factor for a differential equation of the form dydt+P(t)y=Q(t)\frac{dy}{dt} + P(t) y = Q(t)?
  2. How do you solve a homogeneous first-order linear differential equation?
  3. What is the general solution for a separable differential equation?
  4. How do you apply initial conditions to find the particular solution of a differential equation?
  5. What is the significance of the constant CC in the solution of a differential equation?

Tip: Always simplify your integrating factor and check that it fits the form needed to multiply the entire differential equation evenly.

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Math Problem Analysis

Mathematical Concepts

First-order Linear Differential Equation
Integrating Factor
Separation of Variables

Formulas

dy/dt + P(t)y = Q(t) (Standard form of linear first-order differential equation)
Integrating factor: μ(t) = e^(∫ P(t) dt)
Solution form: y = (∫ Q(t) μ(t) dt + C)/μ(t)

Theorems

Method of Integrating Factor
Solution to Linear First-Order Differential Equations

Suitable Grade Level

College/University (Advanced Calculus or Differential Equations)