Math Problem Statement

dy/dt= (9y+8)/t solve the differential equation

Solution

To solve the differential equation:

dydt=9y+8t\frac{dy}{dt} = \frac{9y + 8}{t}

This is a first-order linear differential equation. We can proceed using the method of separation of variables. Here's the step-by-step solution:

Step 1: Rewrite the equation

We want to separate the variables yy and tt to be on different sides of the equation. First, write the equation as:

dydt=9yt+8t\frac{dy}{dt} = \frac{9y}{t} + \frac{8}{t}

Now, rewrite it in the form of dydt=f(t)+g(y)\frac{dy}{dt} = f(t) + g(y):

dydt9yt=8t\frac{dy}{dt} - \frac{9y}{t} = \frac{8}{t}

This is a linear first-order equation of the form dydt+P(t)y=Q(t)\frac{dy}{dt} + P(t) y = Q(t), where P(t)=9tP(t) = -\frac{9}{t} and Q(t)=8tQ(t) = \frac{8}{t}.

Step 2: Find the integrating factor

The integrating factor is given by:

μ(t)=eP(t)dt\mu(t) = e^{\int P(t) \, dt}

Substitute P(t)=9tP(t) = -\frac{9}{t}:

μ(t)=e9tdt=e9lnt=t9\mu(t) = e^{\int -\frac{9}{t} \, dt} = e^{-9 \ln t} = t^{-9}

Step 3: Multiply through by the integrating factor

Multiply the entire differential equation by μ(t)=t9\mu(t) = t^{-9}:

t9dydt9ytt9=8tt9t^{-9} \frac{dy}{dt} - \frac{9y}{t} t^{-9} = \frac{8}{t} t^{-9}

Simplifying:

t9dydt9yt10=8t10t^{-9} \frac{dy}{dt} - 9y t^{-10} = 8 t^{-10}

Now, the left-hand side is a perfect derivative:

ddt(yt9)=8t10\frac{d}{dt} \left( y t^{-9} \right) = 8 t^{-10}

Step 4: Integrate both sides

Now, integrate both sides with respect to tt:

ddt(yt9)dt=8t10dt\int \frac{d}{dt} \left( y t^{-9} \right) \, dt = \int 8 t^{-10} \, dt

The left side integrates to yt9y t^{-9}, and the right side integrates to:

8t10dt=89t9=89t9\int 8 t^{-10} \, dt = \frac{8}{-9} t^{-9} = -\frac{8}{9} t^{-9}

So we have:

yt9=89t9+Cy t^{-9} = -\frac{8}{9} t^{-9} + C

Step 5: Solve for yy

Now, multiply through by t9t^9 to solve for yy:

y=89+Ct9y = -\frac{8}{9} + C t^9

Thus, the general solution to the differential equation is:

y(t)=Ct989y(t) = C t^9 - \frac{8}{9}

where CC is an arbitrary constant determined by initial conditions, if provided.


Would you like more details or have any questions? Here are some related questions you might find interesting:

  1. What is the interpretation of the integrating factor in solving differential equations?
  2. How does the separation of variables method work in nonlinear differential equations?
  3. Can this method be used for equations with other types of terms, such as non-linear ones?
  4. What is the significance of finding the general solution to a differential equation?
  5. How would you apply initial conditions to determine the constant CC?

Tip: Always check whether a differential equation is separable or linear first, as it simplifies the solving process significantly.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Linear First-Order Differential Equations
Integrating Factor Method

Formulas

Integrating factor formula: μ(t) = e^(∫P(t) dt)
General solution of linear first-order differential equations: y(t) = (1/μ(t)) ∫(μ(t)Q(t)) dt + C

Theorems

Linear First-Order Differential Equation Theorem

Suitable Grade Level

Undergraduate Level (Calculus II or Differential Equations Course)