Math Problem Statement

2x+4y=? x=1, y=5

Solution

To solve 2x+4y2x + 4y, substitute x=1x = 1 and y=5y = 5 into the expression:

2x+4y=2(1)+4(5)2x + 4y = 2(1) + 4(5)

=2+20= 2 + 20

=22= 22

The result is:

2x+4y=222x + 4y = 22

Would you like me to explain further or clarify any steps?


5 Related Questions:

  1. What happens if xx and yy are negative values?
  2. How do you solve 3x+2y3x + 2y with the same values of x=1x = 1 and y=5y = 5?
  3. What if the expression was 2x2+4y22x^2 + 4y^2 instead?
  4. Can you create an equation where 2x+4y=502x + 4y = 50?
  5. How would the answer change if x=2x = 2 and y=3y = 3?

Tip:

Always simplify the equation step by step to avoid calculation errors.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Substitution

Formulas

General linear equation: ax + by

Theorems

Basic arithmetic operations and substitution principles

Suitable Grade Level

Grades 6-8