Under her cell phone plan, Sadie pays a flat cost of $61.50 per month and $4 per gigabyte. She wants to keep her bill at $75.50 per month. Write and solve an equation which can be used to determine g*g*, the number of gigabytes of data Sadie can use while staying within her budget.

To find the number of gigabytes of data, $ g $, that Sadie can use while keeping her bill at $ 75.50 $ per month, we can create an equation based on the information provided.

1. Sadie pays a flat rate of $ 61.50 $ per month.
2. She also pays $ 4 $ dollars per gigabyte of data used.
3. She wants her total bill to be $ 75.50 $.

Let $ g $ represent the number of gigabytes she can use. The total cost is the sum of the flat rate and the cost of data usage, which is $ 4g $. Therefore, the equation can be written as:

\[
61.50 + 4g = 75.50
\]

### Solving the equation:

1. Subtract $ 61.50 $ from both sides:

\[
4g = 75.50 - 61.50
\]

\[
4g = 14
\]

2. Divide both sides by $ 4 $:

\[
g = \frac{14}{4}
\]

\[
g = 3.5
\]

### Conclusion:
Sadie can use **3.5 gigabytes** of data while keeping her bill at $ 75.50 $ per month.

Would you like more details or explanations?

### Related questions:
1. What if Sadie’s budget was $80? How would that change the equation?
2. How would the equation change if the cost per gigabyte increased to $5?
3. How can Sadie reduce her bill if she typically uses more than 3.5 gigabytes?
4. What would her bill be if she used 5 gigabytes of data?


Under her cell phone plan, Sadie pays a flat cost of $61.50 per month and $4 per gigabyte. She wants to keep her bill at $75.50 per month. Write and solve an equation which can be used to determine g, the number of gigabytes of data Sadie can use while staying within her budget.

Learn how to solve a linear equation to determine how many gigabytes of data Sadie can use while staying within a $75.50 monthly phone bill. This step-by-step guide uses algebra to solve real-world problems, suitable for Grades 6-8 students.

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