Under his cell phone plan, Suav pays a flat cost of $39 per month and $4 per gigabyte. He wants to keep his bill at $45.40 per month. Write and solve an equation which can be used to determine xx, the number of gigabytes of data Suav can use while staying within his budget.

Let's define the variables and the equation based on the given information:

- Suav pays a flat cost of $39 per month.
- He also pays $4 per gigabyte of data used.
- He wants to keep his total monthly bill at $45.40.
- Let $ x $ represent the number of gigabytes of data Suav can use.

The total cost Suav pays each month is the sum of the flat cost and the cost for the data he uses. Therefore, we can write the equation as:

\[
39 + 4x = 45.40
\]

Now, let's solve for $ x $ (the number of gigabytes Suav can use):

\[
4x = 45.40 - 39
\]
\[
4x = 6.40
\]
\[
x = \frac{6.40}{4}
\]
\[
x = 1.6
\]

Thus, Suav can use **1.6 gigabytes** of data while keeping his bill at $45.40 per month.

Would you like more details on solving linear equations or clarifying any step?

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Here are 5 related questions to extend your understanding:
1. What would Suav's total bill be if he used 3 gigabytes of data in a month?
2. How would the equation change if the flat cost increased to $42 per month?
3. What is the maximum number of gigabytes Suav could use if his budget increased to $50?
4. How would Suav's cost change if the price per gigabyte dropped to $3?
5. What equation would you set up if Suav had a limit of $60 per month and a cost of $5 per gigabyte?

**Tip:** Always isolate the variable by performing inverse operations to solve an equation effectively.

Under his cell phone plan, Suav pays a flat cost of $39 per month and $4 per gigabyte. He wants to keep his bill at $45.40 per month. Write and solve an equation which can be used to determine x, the number of gigabytes of data Suav can use while staying within his budget.

Learn how to solve a linear equation to determine the number of gigabytes of data Suav can use while staying within a $45.40 budget. This problem involves basic algebraic concepts and cost analysis, making it suitable for students in Grades 6-8.

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