Math Problem Statement

a=2\left(b-c\right) solve for b

Solution

To solve the equation a=2(bc)a = 2(b - c) for bb, follow these steps:

  1. Distribute the 2 on the right side:

a=2b2ca = 2b - 2c

  1. Isolate the term containing bb by adding 2c2c to both sides:

a+2c=2ba + 2c = 2b

  1. Solve for bb by dividing both sides by 2:

b=a+2c2b = \frac{a + 2c}{2}

Thus, the solution for bb is:

b=a+2c2\boxed{b = \frac{a + 2c}{2}}

Would you like a more detailed explanation or have any questions?

Related Questions:

  1. How would you solve for cc in the equation a=2(bc)a = 2(b - c)?
  2. If a=10a = 10 and c=3c = 3, what is the value of bb?
  3. What happens to the value of bb if aa is doubled?
  4. How can this equation be represented graphically?
  5. What if the equation was a=3(bc)a = 3(b - c) instead?

Tip: Remember that isolating a variable involves performing inverse operations to both sides of the equation.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

b = (a + 2c) / 2

Theorems

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Suitable Grade Level

Grades 8-10