Math Problem Statement

Solve 2b + 3m = a + 3 for b.

Solution

The equation in the image is:

2b+3m=a+32b + 3m = a + 3

We need to solve for bb.

Solution:

  1. Start by isolating bb on one side of the equation: 2b=a+33m2b = a + 3 - 3m

  2. Now, divide both sides by 2 to solve for bb: b=a+33m2b = \frac{a + 3 - 3m}{2}

So, the solution for bb is:

b=a+33m2b = \frac{a + 3 - 3m}{2}

Would you like a detailed breakdown of any particular step?

Here are 5 related questions for further exploration:

  1. How would you isolate mm instead of bb in the equation 2b+3m=a+32b + 3m = a + 3?
  2. What is the solution for bb if a=5a = 5 and m=2m = 2?
  3. How does the equation change if you add 5 to both sides?
  4. How can you verify the solution for bb is correct?
  5. What would be the effect on bb if the coefficient of mm was doubled?

Tip: Always check your solution by substituting it back into the original equation to ensure it satisfies the given condition.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Variable Isolation

Formulas

b = (a + 3 - 3m) / 2

Theorems

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Suitable Grade Level

Grades 7-10