To solve for $c$ in the equation $3ab - 2bc = 12$, follow these steps:

Step 1: Isolate the term with $c$

We want to move all terms involving $c$ to one side. Start by subtracting $3ab$ from both sides of the equation:

$-2bc = 12 - 3ab$

Step 2: Solve for $c$

Now, divide both sides of the equation by $-2b$ to isolate $c$:

$c = \frac{12 - 3ab}{-2b}$

Step 3: Simplify the expression

You can simplify the fraction by factoring out the negative sign:

$c = \frac{-(12 - 3ab)}{2b}$

or

$c = \frac{3ab - 12}{2b}$

This is the solution for $c$.

Would you like further details or have any questions?

Here are 5 related questions to practice:

1. Solve $4xy - 5yz = 20$ for $z$.
2. Solve $2ab - 3ac = 15$ for $c$.
3. If $3ab - 2bc = 0$, solve for $c$.
4. Solve $6xy + 2yz = 10$ for $z$.
5. Solve $5ac + 7bc = 25$ for $c$.

Tip: When solving for a variable, always aim to isolate that variable on one side of the equation by using inverse operations (e.g., addition, subtraction, multiplication, division).