To solve the equation \(-3y + 6 = -18\), follow these steps:

1. **Subtract 6 from both sides** to isolate the term with \(y\):
   \[
   -3y + 6 - 6 = -18 - 6
   \]
   Simplifying both sides:
   \[
   -3y = -24
   \]

2. **Divide both sides by \(-3\)** to solve for \(y\):
   \[
   y = \frac{-24}{-3}
   \]
   Simplifying the right side:
   \[
   y = 8
   \]

The solution is \(y = 8\).

Would you like more details on solving this type of equation?

Here are five related questions:
1. How would you solve \(4y - 5 = 11\)?
2. What happens if the equation has variables on both sides?
3. How do you solve a system of equations with two variables?
4. Can you solve equations with fractions, like \(\frac{2}{3}y + 4 = 10\)?
5. How does solving inequalities differ from solving equalities?

**Tip:** Always perform the same operation on both sides of an equation to maintain balance.

Discover how to solve the linear equation -3y + 6 = -18 using simple algebraic steps. This solution demonstrates the application of the addition and division properties of equality, ideal for students in Grades 6-8.

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