We are given the equation:

\[
2(3y - 9) = 18
\]

Let's solve for \( y \):

### Step 1: Expand the parentheses.
\[
2 \times (3y) - 2 \times (9) = 18
\]
\[
6y - 18 = 18
\]

### Step 2: Add 18 to both sides to isolate the term with \( y \).
\[
6y = 18 + 18
\]
\[
6y = 36
\]

### Step 3: Divide both sides by 6.
\[
y = \frac{36}{6}
\]
\[
y = 6
\]

So, the solution is \( y = 6 \).

Would you like more details or further clarification?

Here are 5 related questions to expand your understanding:
1. What happens if the equation is \( 2(3y - 9) = 36 \)?
2. How do you solve \( 3(4y - 5) = 12 \)?
3. What if the equation was \( 2(3y - 9) + 5 = 18 \)?
4. How do you check if your solution is correct?
5. Can you solve \( 5(y + 4) = 3y + 12 \)?

**Tip:** Always remember to expand and simplify equations before isolating the variable.

Learn how to solve the linear equation 2(3y - 9) = 18 with a detailed step-by-step solution. This problem covers key algebraic concepts, such as the distributive property and isolating the variable y. Suitable for students in Grades 6-8.

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