You have the equation:

\[
1200 = 200 - a - b
\]

Let's solve for \( a + b \) first by isolating the terms with \( a \) and \( b \) on one side:

\[
1200 - 200 = -a - b
\]

Simplifying:

\[
1000 = -a - b
\]

Multiplying the whole equation by \(-1\) to get rid of the negative signs:

\[
a + b = -1000
\]

Thus, the equation simplifies to:

\[
a + b = -1000
\]

Would you like more details or have any questions?

Here are 5 related questions:
1. If \( a = 500 \), what is the value of \( b \)?
2. How would this equation change if \( 1200 \) were increased by 300?
3. What happens to \( a + b \) if both sides of the equation are divided by 2?
4. How can this equation be used to model real-life scenarios?
5. What if the equation had more terms, such as \( 1200 = 200 - a - b + c \)?

**Tip:** When solving linear equations, always aim to isolate the variable terms step by step!

Learn how to solve the linear equation 1200 = 200 - a - b with step-by-step guidance. Discover key algebraic techniques and solve for a + b. This problem is suitable for students in Grades 6-8 and covers essential concepts of algebra and linear equations.

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