To solve for \( a \) in the equation \( 5a + 2b = 40 \), you need to isolate \( a \). Here's how you can do it step-by-step:

1. Start with the given equation:
   \[
   5a + 2b = 40
   \]

2. Subtract \( 2b \) from both sides of the equation to isolate the term with \( a \):
   \[
   5a = 40 - 2b
   \]

3. Divide both sides by 5 to solve for \( a \):
   \[
   a = \frac{40 - 2b}{5}
   \]

4. Simplify the equation if possible:
   \[
   a = 8 - \frac{2b}{5}
   \]

So, the solution for \( a \) in terms of \( b \) is:
\[
a = 8 - \frac{2b}{5}
\]

Would you like further details or have any questions?

Here are 5 related questions to expand your understanding:

1. If \( b = 10 \), what is the value of \( a \)?
2. How would you solve for \( b \) in terms of \( a \) in the equation \( 5a + 2b = 40 \)?
3. What is the value of \( a \) when \( b = 0 \)?
4. How would you graph the equation \( 5a + 2b = 40 \) on the \( a \)-\( b \) plane?
5. Can you find the intercepts of the equation \( 5a + 2b = 40 \)?

**Tip:** When solving linear equations, always aim to isolate the variable you are solving for by performing inverse operations systematically.

Learn how to solve the linear equation 5a + 2b = 40 for the variable 'a'. This problem covers key algebraic concepts, including isolating variables and applying properties of equality. Suitable for students in Grades 6-8.

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