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The problem asks to find \((g \circ f)(2)\), where \(f(x) = 2x + 3\) and \(g(x) = x^2 - 7\).

### Steps:
1. First, find \(f(2)\):
   \[
   f(2) = 2(2) + 3 = 4 + 3 = 7
   \]

2. Now, substitute \(f(2) = 7\) into \(g(x)\):
   \[
   g(7) = 7^2 - 7 = 49 - 7 = 42
   \]

Thus, \((g \circ f)(2) = 42\).

Would you like more details or have any questions?

### Follow-up questions:
1. How do you find the composition of two functions in general?
2. Can you explain why \(g(f(x))\) is different from \(f(g(x))\)?
3. How would you approach this problem if the functions were different?
4. What happens when you reverse the composition and compute \(f(g(2))\)?
5. How do you interpret compositions of functions graphically?

**Tip:** When working with compositions of functions, remember that you always evaluate the innermost function first and work your way outward.

Let f(x) = 2x + 3 and g(x) = x^2 - 7. Find (g ∘ f)(2).

Learn how to solve function composition with f(x) = 2x + 3 and g(x) = x^2 - 7 to find (g ∘ f)(2). This example demonstrates the steps of evaluating functions and is suitable for Grades 9-10.

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