Math Problem Statement

Solve the expression: 3 + (3/8) ÷ 6 - (2/4).

Solution

The given mathematical expression is:

3+38÷6243 + \frac{3}{8} \div 6 - \frac{2}{4}

Let's solve this step by step.

  1. Division: Start by performing the division of 38÷6\frac{3}{8} \div 6. To divide by 6, multiply by the reciprocal of 6:

    38÷6=38×16=3×18×6=348=116\frac{3}{8} \div 6 = \frac{3}{8} \times \frac{1}{6} = \frac{3 \times 1}{8 \times 6} = \frac{3}{48} = \frac{1}{16}

  2. Substitution: Now substitute this result back into the equation:

    3+116243 + \frac{1}{16} - \frac{2}{4}

  3. Simplify the subtraction: Simplify 24\frac{2}{4}, which is equal to 12\frac{1}{2}.

  4. Substitute and combine terms: The expression is now:

    3+116123 + \frac{1}{16} - \frac{1}{2}

    To combine these terms, we need a common denominator. The common denominator for 16 and 2 is 16. Convert 12\frac{1}{2} to 816\frac{8}{16}.

    Now, the expression becomes:

    3+1168163 + \frac{1}{16} - \frac{8}{16}

    Combine the fractions:

    3+1816=37163 + \frac{1 - 8}{16} = 3 - \frac{7}{16}

  5. Final calculation: Now subtract 716\frac{7}{16} from 3:

    3716=4816716=48716=41163 - \frac{7}{16} = \frac{48}{16} - \frac{7}{16} = \frac{48 - 7}{16} = \frac{41}{16}

    This is equivalent to:

    29162 \frac{9}{16}

Thus, the correct answer is A. 29162 \frac{9}{16}.


Would you like more details on any step?

Here are 5 related questions:

  1. How do you divide fractions?
  2. Why do we need a common denominator when adding or subtracting fractions?
  3. How do you convert an improper fraction to a mixed number?
  4. What is the reciprocal of a number, and how is it used in division?
  5. How can you simplify a fraction like 24\frac{2}{4}?

Tip: Always perform operations in the correct order (division/multiplication before addition/subtraction) to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Fractions
Arithmetic Operations
Order of Operations

Formulas

Division of Fractions
Simplification of Fractions
Combining Fractions with Common Denominators

Theorems

Order of Operations (PEMDAS/BODMAS)

Suitable Grade Level

Grades 6-8