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The given mathematical expression is:

\[
3 + \frac{3}{8} \div 6 - \frac{2}{4}
\]

Let's solve this step by step.

1. **Division**: Start by performing the division of \(\frac{3}{8} \div 6\). To divide by 6, multiply by the reciprocal of 6:
   
   \[
   \frac{3}{8} \div 6 = \frac{3}{8} \times \frac{1}{6} = \frac{3 \times 1}{8 \times 6} = \frac{3}{48} = \frac{1}{16}
   \]

2. **Substitution**: Now substitute this result back into the equation:
   
   \[
   3 + \frac{1}{16} - \frac{2}{4}
   \]

3. **Simplify the subtraction**: Simplify \(\frac{2}{4}\), which is equal to \(\frac{1}{2}\).

4. **Substitute and combine terms**: The expression is now:
   
   \[
   3 + \frac{1}{16} - \frac{1}{2}
   \]

   To combine these terms, we need a common denominator. The common denominator for 16 and 2 is 16. Convert \(\frac{1}{2}\) to \(\frac{8}{16}\).

   Now, the expression becomes:
   
   \[
   3 + \frac{1}{16} - \frac{8}{16}
   \]

   Combine the fractions:
   
   \[
   3 + \frac{1 - 8}{16} = 3 - \frac{7}{16}
   \]

5. **Final calculation**: Now subtract \(\frac{7}{16}\) from 3:
   
   \[
   3 - \frac{7}{16} = \frac{48}{16} - \frac{7}{16} = \frac{48 - 7}{16} = \frac{41}{16}
   \]

   This is equivalent to:
   
   \[
   2 \frac{9}{16}
   \]

Thus, the correct answer is **A. \( 2 \frac{9}{16} \)**.

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Would you like more details on any step?

Here are 5 related questions:
1. How do you divide fractions?
2. Why do we need a common denominator when adding or subtracting fractions?
3. How do you convert an improper fraction to a mixed number?
4. What is the reciprocal of a number, and how is it used in division?
5. How can you simplify a fraction like \(\frac{2}{4}\)?

**Tip**: Always perform operations in the correct order (division/multiplication before addition/subtraction) to avoid errors.

Solve the expression: 3 + (3/8) ÷ 6 - (2/4).

Learn how to solve a complex expression involving addition, division, and subtraction of fractions. This detailed step-by-step solution walks through using common denominators, simplifying fractions, and following the order of operations. Ideal for students in Grades 6-8.

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