To solve for \( b \) in the equation \( xb - 1 = k \):

1. **Add 1 to both sides** of the equation to isolate the term involving \( b \):

\[
xb = k + 1
\]

2. **Divide both sides** of the equation by \( x \) to solve for \( b \):

\[
b = \frac{k + 1}{x}
\]

So, the solution for \( b \) is:

\[
b = \frac{k + 1}{x}
\]

Would you like more details or have any questions?

Here are 5 related questions:

1. How do you solve for \( b \) if the equation is \( b - x = k \)?
2. What happens to \( b \) when \( x = 0 \) in the original equation?
3. Can you solve for \( x \) instead of \( b \) in the equation \( xb - 1 = k \)?
4. How do you graph the function \( b(x) = \frac{k + 1}{x} \)?
5. What is the domain of the function \( b(x) = \frac{k + 1}{x} \)?

**Tip:** When isolating a variable, always perform the inverse operation to both sides of the equation.

Learn how to solve the equation xb - 1 = k to find the value of b. Follow a detailed step-by-step solution including adding 1 to both sides and dividing by x. This problem involves solving linear equations and is suitable for Grades 7-9.

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