The given equation is:

\[
7b - 3k = c + 1
\]

You can rearrange this equation to solve for any of the variables. Let's solve for each variable:

### 1. Solve for \(b\):
\[
7b = c + 1 + 3k
\]
\[
b = \frac{c + 1 + 3k}{7}
\]

### 2. Solve for \(k\):
\[
-3k = c + 1 - 7b
\]
\[
k = \frac{7b - c - 1}{3}
\]

### 3. Solve for \(c\):
\[
c = 7b - 3k - 1
\]

Let me know if you need further details on solving for one of these variables or a specific explanation!

Here are 5 related questions you could explore:
1. How would you solve for \(b\) if there was a coefficient in front of \(c\)?
2. What happens if you substitute specific values for \(b\) and \(k\)?
3. How would the solution change if the equation had an additional constant term on the left-hand side?
4. How can this equation be graphed in three dimensions?
5. What are the restrictions on the variables \(b\), \(k\), and \(c\) if they are required to be integers?

**Tip:** When solving for a variable, always isolate the target variable on one side of the equation step by step.

Explore how to solve the linear equation 7b - 3k = c + 1 step by step. Learn the key algebraic techniques used to isolate variables and rearrange the equation. This problem covers fundamental algebra concepts and is suitable for students in Grades 8-10.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation