Math Problem Statement

Find the value of x in the given circle geometry diagram where angle PRQ = 22° and angle QSR = 28°.

Solution

To solve for xx in the given diagram, we will apply some basic theorems related to circles and angles.

Key Observations:

  • PRQ=22\angle PRQ = 22^\circ
  • QSR=28\angle QSR = 28^\circ
  • xx is the angle at QQ.

Strategy:

  1. Cyclic Quadrilateral Theorem: In a cyclic quadrilateral (where all vertices lie on the circle), the sum of opposite angles is 180180^\circ.

    This means that: PRQ+PSQ=180\angle PRQ + \angle PSQ = 180^\circ Given that PRQ=22\angle PRQ = 22^\circ, we can find PSQ\angle PSQ.

  2. Angles in the Same Segment: Angles subtended by the same arc (or chord) at the circumference of a circle are equal.

Thus, using the theorem and relations, we can proceed:

Step-by-Step Solution:

  1. Use the Cyclic Quadrilateral Theorem to find PSQ\angle PSQ: PRQ+PSQ=180\angle PRQ + \angle PSQ = 180^\circ 22+PSQ=18022^\circ + \angle PSQ = 180^\circ PSQ=18022=158\angle PSQ = 180^\circ - 22^\circ = 158^\circ

  2. Now, notice that xx and 2828^\circ are on the same arc PQPQ. Since the angles subtended by the same arc are equal, we can set: x=28x = 28^\circ

Thus, the value of xx is 28\boxed{28^\circ}.

Let me know if you'd like any further clarification!


Related Questions:

  1. What is the Cyclic Quadrilateral Theorem and how is it used in circle geometry?
  2. How do you find the measure of an angle subtended by the same arc?
  3. What are the properties of angles in a cyclic quadrilateral?
  4. Can we apply the Inscribed Angle Theorem to solve other circle geometry problems?
  5. How can angle chasing be useful in solving complex circle geometry problems?

Tip:

Remember that angles subtended by the same arc in a circle are always equal, which is a powerful tool in circle geometry.

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Math Problem Analysis

Mathematical Concepts

Circle Geometry
Cyclic Quadrilaterals
Angles in Circles

Formulas

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Theorems

Cyclic Quadrilateral Theorem
Angles in the Same Segment Theorem

Suitable Grade Level

Grades 9-11