Math Problem Statement

Step by step solution using linear differential equation

Step by step solution using linear differential equation

Solution

The equation you provided is:

y=1+2xyy' = 1 + 2xy

This is a first-order non-linear differential equation. To solve it, we will use an appropriate method such as the integrating factor, substitution, or other relevant techniques based on its structure. Here, it resembles a Bernoulli equation after a transformation.

Let's go through the solution step by step.

Step 1: Rewrite the Equation

The given equation is:

dydx=1+2xy\frac{dy}{dx} = 1 + 2xy

We can rearrange this as:

dydx2xy=1\frac{dy}{dx} - 2xy = 1

Step 2: Try the Method of an Integrating Factor

This equation looks like a linear differential equation of the form:

dydx+P(x)y=Q(x)\frac{dy}{dx} + P(x)y = Q(x)

Where:

  • P(x)=2xP(x) = -2x
  • Q(x)=1Q(x) = 1

The general method for solving such linear differential equations involves finding an integrating factor μ(x)\mu(x), which is given by:

μ(x)=eP(x)dx\mu(x) = e^{\int P(x)dx}

So, for this equation:

μ(x)=e2xdx=ex2\mu(x) = e^{\int -2x \, dx} = e^{-x^2}

Step 3: Multiply Through by the Integrating Factor

Multiply both sides of the differential equation by ex2e^{-x^2}:

ex2dydx2xex2y=ex2e^{-x^2} \frac{dy}{dx} - 2xe^{-x^2}y = e^{-x^2}

The left-hand side is now the derivative of yex2y \cdot e^{-x^2}:

ddx(yex2)=ex2\frac{d}{dx}(y \cdot e^{-x^2}) = e^{-x^2}

Step 4: Integrate Both Sides

Now integrate both sides with respect to xx:

yex2=ex2dxy \cdot e^{-x^2} = \int e^{-x^2} dx

The integral ex2dx\int e^{-x^2} dx does not have an elementary function, so we denote it as the error function erf(x)\text{erf}(x). Therefore, we write the general solution as:

yex2=C+erf(x)y \cdot e^{-x^2} = C + \text{erf}(x)

Where CC is the constant of integration.

Step 5: Solve for yy

Finally, solve for yy:

y=(C+erf(x))ex2y = \left(C + \text{erf}(x)\right) e^{x^2}

Final Solution:

y(x)=(C+erf(x))ex2y(x) = \left(C + \text{erf}(x)\right) e^{x^2}

This is the general solution to the given differential equation.

Would you like more details on any part of this process or have any specific questions?

Related Questions:

  1. What are the conditions under which the integrating factor method is applicable?
  2. How do you compute the error function erf(x)\text{erf}(x) in practice?
  3. What are some examples of differential equations where the solution includes special functions like erf(x)\text{erf}(x)?
  4. Can the integrating factor method be used to solve non-linear equations directly?
  5. What other methods can solve first-order non-linear differential equations like this one?

Tip: In some cases, even when an equation has no elementary solution, special functions like the error function can be very useful in expressing the solution!

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Math Problem Analysis

Mathematical Concepts

First-order differential equation
Integrating factor
Bernoulli equation

Formulas

Linear differential equation form: y' + P(x)y = Q(x)
Integrating factor: μ(x) = e^{∫P(x) dx}

Theorems

Integrating factor method
Error function

Suitable Grade Level

College-level calculus