To solve the expression \( 4^2 + 3 \times (6 - 2) \), we will use the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

1. **Parentheses**: First, solve the expression inside the parentheses:
   \[
   6 - 2 = 4
   \]

2. **Exponents**: Next, calculate the exponent:
   \[
   4^2 = 16
   \]

3. **Multiplication**: Then, perform the multiplication:
   \[
   3 \times 4 = 12
   \]

4. **Addition**: Finally, add the results:
   \[
   16 + 12 = 28
   \]

Therefore, the value of the expression \( 4^2 + 3 \times (6 - 2) \) is \( 28 \).

Would you like more details or have any questions?

Here are some related questions to consider:
1. What if the expression was \( 4^2 + 3 \times (6 - 3) \)?
2. How would the result change if the exponent was \( 4^3 \) instead of \( 4^2 \)?
3. How does adding more operations affect the complexity of solving such expressions?
4. What happens if there are nested parentheses, like \( 4^2 + 3 \times (6 - (2 + 1)) \)?
5. How would the expression change if the multiplication was replaced with division, such as \( 4^2 + 3 \div (6 - 2) \)?

**Tip:** Always remember to perform multiplication and division before addition and subtraction, unless parentheses indicate otherwise!

Learn how to solve the expression 4^2 + 3*(6-2) step-by-step with detailed explanations. This problem covers order of operations, exponents, parentheses, multiplication, and addition. Suitable for students in Grades 5-7.

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