Math Problem Statement

Solve for π‘₯ in the following expression. Enter your answer in decimal form, rounded to four decimal places. If an answer does not exist, enter DNE.

2𝑒^(π‘₯/5)βˆ’8=0

π‘₯ =

Solution

We are tasked with solving the equation:

2ex5βˆ’8=02e^{\frac{x}{5}} - 8 = 0

Step-by-Step Solution:

  1. Isolate the exponential term: 2ex5=82e^{\frac{x}{5}} = 8

  2. Divide both sides by 2: ex5=4e^{\frac{x}{5}} = 4

  3. Take the natural logarithm (ln) of both sides: ln⁑(ex5)=ln⁑(4)\ln\left(e^{\frac{x}{5}}\right) = \ln(4)

  4. Simplify using the logarithmic identity ln⁑(ea)=a\ln(e^a) = a: x5=ln⁑(4)\frac{x}{5} = \ln(4)

  5. Solve for xx by multiplying both sides by 5: x=5ln⁑(4)x = 5 \ln(4)

  6. Calculate ln⁑(4)\ln(4) and multiply by 5: x=5Γ—1.3863=6.9315x = 5 \times 1.3863 = 6.9315

Final Answer:

xβ‰ˆ6.9315x \approx 6.9315

Let me know if you want more details on this problem, and here are some related questions for further practice:

  1. Solve 3ex4βˆ’9=03e^{\frac{x}{4}} - 9 = 0.
  2. Find the value of xx if 5ex=105e^{x} = 10.
  3. Solve e2xβˆ’7=0e^{2x} - 7 = 0.
  4. Determine xx if 4ex3=124e^{\frac{x}{3}} = 12.
  5. Solve 6exβˆ’18=06e^{x} - 18 = 0.

Tip: When dealing with exponential equations, using natural logarithms is often the easiest way to isolate and solve for xx.

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Math Problem Analysis

Mathematical Concepts

Exponential Equations
Logarithms

Formulas

e^(x) = y
ln(e^a) = a

Theorems

Logarithmic Identity

Suitable Grade Level

Grades 10-12