To solve the equation $x^2 = 81$, we need to find the values of $x$ that satisfy this equation.

Solution:

1. Start with the equation: $x^2 = 81$

2. Take the square root of both sides: $x = \pm \sqrt{81}$

3. Simplify the square root: $\sqrt{81} = 9$

4. Include both positive and negative solutions: $x = 9 \quad \text{or} \quad x = -9$

Final Answer:

$x = 9 \quad \text{or} \quad x = -9$

Would you like more details or have any questions about this solution?

Related Questions:

1. How would you solve $x^2 = 100$?
2. What are the solutions to $x^2 = 64$?
3. Can you find the roots of $x^2 = 49$?
4. How do you solve $x^2 = 25$?
5. What are the solutions to $x^2 = 144$?
6. How would you solve $x^2 = 36$?
7. Can you find the roots of $x^2 = 121$?
8. What is the solution to $x^2 = 16$?

Tip:

When solving quadratic equations of the form $x^2 = a$, always remember to consider both the positive and negative square roots of $a$.