https://file.aiquickdraw.com/mathbot/file/173007233985487nc8es1.jpg

The problem shown in the image is:

**Solve \( x^2 = 81 \)**

To solve for \( x \), follow these steps:

1. Rewrite the equation:
   \[
   x^2 = 81
   \]

2. Take the square root of both sides:
   \[
   x = \pm \sqrt{81}
   \]

3. Calculate the square root:
   \[
   x = \pm 9
   \]

So the solutions are \( x = 9 \) and \( x = -9 \).

The correct answer is therefore:
**C. \(-9, 9\)**

Would you like a more detailed explanation, or do you have any other questions?

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Here are some related questions for further practice:

1. What are the solutions to \( x^2 = 49 \)?
2. How would you solve \( x^2 = 100 \)?
3. If \( x^2 = 144 \), what are the possible values of \( x \)?
4. What is the solution to \( x^2 = 25 \)?
5. How do we solve \( x^2 = 121 \)?

**Tip:** Remember that taking the square root of both sides of an equation involving \( x^2 \) requires considering both the positive and negative roots.

Learn how to solve x^2 = 81 by applying square roots to find both positive and negative solutions. This problem covers fundamental algebra concepts, making it suitable for students in grades 8 to 10.

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