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To solve the definite integral \(\int_{-5}^{3} (-7) \, dp\), we can follow these steps:

1. The integrand \(-7\) is a constant.
2. The integral of a constant \(c\) with respect to \(p\) is \(c \cdot p\).

So, we have:
\[
\int_{-5}^{3} (-7) \, dp = -7 \int_{-5}^{3} 1 \, dp = -7 \left[ p \right]_{-5}^{3}
\]

3. Evaluate the integral by applying the limits:
\[
-7 \left[ p \right]_{-5}^{3} = -7 \left( 3 - (-5) \right) = -7 (3 + 5) = -7 \cdot 8 = -56
\]

Therefore,
\[
\int_{-5}^{3} (-7) \, dp = -56
\]

If you have any questions or need further details, feel free to ask!

Here are 5 questions you can ask next:
1. How do you find the antiderivative of a polynomial function?
2. What are the properties of definite integrals?
3. Can you explain the Fundamental Theorem of Calculus?
4. How do you solve an integral involving trigonometric functions?
5. What is the method to integrate by parts?

**Tip:** When dealing with definite integrals, always remember to apply the limits of integration correctly after finding the antiderivative.

Learn how to solve the definite integral \(\int_{-5}^{3} (-7) \, dp\) with a detailed step-by-step solution. This problem involves integrating a constant function over specified limits. Suitable for students in Grades 11-12.

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