Math Problem Statement

Use the digits 3, 4, 6, and 8 once in each of the following to make a true statement. Observe the PMDAS rule.

Solution

Let's solve each of the problems using the digits 3, 4, 6, and 8 exactly once in each equation while following the PMDAS rule (Parentheses, Multiplication and Division, Addition and Subtraction).

  1. (___ + ) ÷ ( + ___) = 2

    Solution: (6+4)÷(8+2)=10÷5=2(6 + 4) ÷ (8 + 2) = 10 ÷ 5 = 2 This does not work, let's try: (8+4)÷(6+2)=12÷6=2(8 + 4) ÷ (6 + 2) = 12 ÷ 6 = 2 This works!

  2. ___ + (___ ÷ ___) x ___ = 12

    Solution: 3+(6÷2)x43 + (6 ÷ 2) x 4

  3. ___ x ___ x ___ ÷ ___ = 9

    Solution: 6x3x2÷46 x 3 x 2 ÷ 4

  4. ___ x (___ x ___) ÷ ___ = 16

    Solution: 3x(4x2)÷63 x (4 x 2) ÷ 6

  5. ___ ÷ (___ ÷ ___) + ___ = 7

    Solution: 8÷(3÷6)8 ÷ (3 ÷ 6)

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Math Problem Analysis

Mathematical Concepts

Arithmetic
Algebra
Order of Operations

Formulas

Basic arithmetic operations: Addition, Subtraction, Multiplication, Division

Theorems

PMDAS (Parentheses, Multiplication, Division, Addition, Subtraction) rule

Suitable Grade Level

Grades 5-7