The image shows a problem involving angles and parallel lines. It mentions that lines $AB$ and $DE$ are parallel. Given some angles, the problem asks to find the values of $\angle ACB$ and $\angle BCE$.

Information extracted:

1. $\angle B = 70^\circ$
2. $\angle ACD = 60^\circ$
3. There is an intersection at point $C$, where lines $AB$ and $DE$ meet.

We need to apply the properties of parallel lines and angle relationships (like alternate interior angles, corresponding angles, and the sum of angles in a triangle) to find the unknown angles.

I will now solve the problem.

Finding $\angle ACB$:

From the diagram, $AB \parallel DE$, and $CD$ acts as a transversal between these parallel lines. Since $\angle ACD = 60^\circ$, by alternate interior angle theorem, $\angle ACB = 60^\circ$ as well.

Finding $\angle BCE$:

Using the angle sum property of a triangle: $\angle B + \angle ACB + \angle BCE = 180^\circ$ Substitute the known values: $70^\circ + 60^\circ + \angle BCE = 180^\circ$ $\angle BCE = 180^\circ - 130^\circ = 50^\circ$

Thus, $\angle ACB = 60^\circ$ and $\angle BCE = 50^\circ$.

Would you like further details or have any other questions?

Here are 5 related questions to expand on this topic:

1. How are alternate interior angles formed in parallel line setups?
2. What are corresponding angles, and how do they relate to parallel lines?
3. Can you solve for the exterior angles in the given diagram?
4. What is the angle sum property of a triangle, and why is it always 180°?
5. How do transversal lines affect angle relationships in parallel lines?

Tip: When working with parallel lines and transversals, always look for alternate interior and corresponding angles—they're often key to solving angle-related problems.