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We are given a geometry problem where:

- AB is parallel to EC,
- ∠BCD = 72°,
- We are tasked to find ∠BAC.

### Step-by-step Solution:

1. **Using the property of parallel lines**: 
   Since AB is parallel to EC, the angles ∠BAC and ∠BCD are alternate interior angles. Thus, we have:
   \[
   \text{∠BAC} = \text{∠BCD}
   \]

2. **Given angle**: 
   It is provided that ∠BCD = 72°.

3. **Conclusion**:
   Hence, ∠BAC = 72°.

Thus, the value of ∠BAC is **72°**, and the correct option is (4).

Would you like any further details or explanations?

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### Relative Questions:

1. What is the relationship between alternate interior angles in parallel lines?
2. How do we use the properties of parallel lines to find unknown angles?
3. What is the sum of the interior angles of a triangle, and how can it help in angle calculations?
4. How can we use angle properties in circles (such as cyclic quadrilaterals)?
5. What other problems can be solved using the properties of parallel lines and angles?

### Tip:
When working with angles involving parallel lines, always look for corresponding or alternate angles as they often hold key information for solving the problem.

If AB is parallel to EC and ∠BCD = 72°, what will be the value of ∠BAC?

Learn how to find the value of ∠BAC when AB is parallel to EC and ∠BCD = 72°. This problem uses key geometry concepts such as parallel lines and cyclic quadrilateral theorems. Suitable for students in Grades 9-11.

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