Indah is 6 times older than Richard.

Together, their ages total 91.

Calculate Indah's age.

Let's denote Richard's age as \( x \). According to the problem, Indah is 6 times older than Richard, so her age would be \( 6x \).

The total of their ages is 91, which gives us the equation:

\[
x + 6x = 91
\]

Simplify the equation:

\[
7x = 91
\]

Now, solve for \( x \):

\[
x = \frac{91}{7} = 13
\]

So, Richard is 13 years old. Since Indah is 6 times older than Richard:

\[
6 \times 13 = 78
\]

Thus, Indah is 78 years old.

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Would you like a more detailed explanation or have any questions?

Here are 5 related questions to explore:

1. If Indah were twice as old as Richard, what would their ages be if their total age remained 91?
2. How would their ages change if Richard were 10 years younger, keeping the same relationship?
3. If Indah is currently 78, how old was she when Richard was born?
4. What will their ages be in 10 years?
5. If another person, Sarah, joins and is half Indah's age, what is Sarah’s age?

**Tip:** Always set up relationships with variables and translate word problems into equations for easier solving.

Indah is 6 times older than Richard. Together, their ages total 91. Calculate Indah's age.

Learn how to solve the age word problem where Indah is 6 times older than Richard, and their total ages sum to 91. This example demonstrates how to set up and solve linear equations, suitable for students in Grades 6-8.

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