https://file.aiquickdraw.com/mathbot/file/1727315539789ac21g7z6.jpg

Let’s analyze the problem and set it up step by step.

### Let:
- \( x \) be your current age.
- \( y \) be your daughter's current age.

### Information from the problem:
1. **Seven years ago**, your age was 11 times your daughter's age:
   \[
   x - 7 = 11(y - 7)
   \]
   
2. **Now**, you are 4 times as old as your daughter:
   \[
   x = 4y
   \]

### Step-by-Step Solution:
We can substitute the second equation \( x = 4y \) into the first equation to find \( y \).

#### Substituting \( x = 4y \) into the first equation:
\[
4y - 7 = 11(y - 7)
\]
Expanding both sides:
\[
4y - 7 = 11y - 77
\]
Bringing all terms involving \( y \) to one side:
\[
4y - 11y = -77 + 7
\]
\[
-7y = -70
\]
Dividing by \(-7\):
\[
y = 10
\]

So, your daughter is currently 10 years old.

#### Now, using \( x = 4y \) to find your age:
\[
x = 4 \times 10 = 40
\]

### Final Answer:
You are currently **40 years old**.

Would you like further details or have any other questions? Here are some related questions to expand on this topic:

1. What if you were only 3 times as old as your daughter instead of 4?
2. How would the equation change if the situation happened 5 years ago instead of 7?
3. How can you check the solution by back-substituting values?
4. How does the relationship between your age and your daughter's age change over time?
5. What if the age ratio 7 years ago was different, say 9 times instead of 11?

**Tip**: When solving age problems, always translate word problems into algebraic equations to manage them more easily.

Seven years ago, I was eleven times as old as my daughter. Now I am four times as old as she is. My age is ____.

Learn how to solve an age-related word problem where the current age is four times the daughter's age, and seven years ago, it was eleven times. This problem demonstrates the use of linear equations to solve real-world problems. Suitable for Grades 8-10.

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