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The problem presented in the images reads:

- Richard and Teo have a combined age of 33.
- Richard is 15 years older than twice Teo's age.

We are asked to find their individual ages.

### Let:
- \( R \) = Richard's age
- \( T \) = Teo's age

We can set up the following system of equations from the information provided:

1. \( R + T = 33 \)  (their combined age is 33)
2. \( R = 2T + 15 \) (Richard is 15 years older than twice Teo's age)

### Solving the system:

Substitute the expression for \( R \) from equation (2) into equation (1):

\[
(2T + 15) + T = 33
\]

Simplify:

\[
3T + 15 = 33
\]

Subtract 15 from both sides:

\[
3T = 18
\]

Divide by 3:

\[
T = 6
\]

Now that we know \( T \) (Teo's age), substitute it back into equation (2) to find \( R \):

\[
R = 2(6) + 15 = 12 + 15 = 27
\]

### Conclusion:
- Richard is 27 years old.
- Teo is 6 years old.

Let me know if you would like more details or have any questions! Here are five related questions you can explore:

1. How would the solution change if Richard were 10 years older than twice Teo's age?
2. What if their combined age was 40 instead of 33?
3. Can you solve the problem graphically by plotting the two equations?
4. How would you check your solution to ensure it's correct?
5. What other types of word problems can be solved with systems of linear equations?

**Tip:** When solving word problems, always define your variables clearly and set up equations based on the given relationships!

Richard and Teo have a combined age of 33. Richard is 15 years older than twice Teo's age. How old are Richard and Teo?

Learn how to solve a word problem involving Richard and Teo's combined age of 33, where Richard is 15 years older than twice Teo's age. This problem uses systems of linear equations and is suitable for students in Grades 7-9.

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