Math Problem Statement

A. Write the letter of the correct answer in the space provided before each number. Show your solution

for the following problems. (5pts each)

_____1. Sterling silver contains 93.5% silver, if a necklace made of sterling weighs 15g. What is the mass of the

silver dissolved contained in the necklace?

a. 1.6 g b. 6.2 g c. 9.0 g d. 14.0 g

_____2. Rubbing alcohol is commonly used as an antiseptic for small cuts. It is sold as a 70% solution of

isopropyl alcohol in water. What volume of isopropyl alcohol is used to make 500 mL of rubbing

alcohol?

a. 35.0 mL b. 350 mL c. 3.50 mL d. 0.350 mL

_____3. What is the concentration, in % (m/v) of a solution containing 15.0 g KCl in 600.0 mL solution?

a. 5.00%. b. 2.00% c. 0.200% d. 2.50%

_____4. What volume of 0.250 M KOH solution contains 6.31 grams of KOH?

a. 631 mL b. 28.11 mL c. 450 mL d. 0.449 mL

Solution

Let us solve each question step by step, showing the calculations and reasoning:


Problem 1: Mass of silver in the necklace

Sterling silver contains 93.5% silver, and the necklace weighs 15 g.
We find the mass of silver using:
Mass of silver=Percentage of silver×Total mass\text{Mass of silver} = \text{Percentage of silver} \times \text{Total mass} Substituting the given values:
Mass of silver=0.935×15=14.025g\text{Mass of silver} = 0.935 \times 15 = 14.025 \, \text{g}

Correct Answer: d. 14.0 g


Problem 2: Volume of isopropyl alcohol in 500 mL solution

Rubbing alcohol is 70% isopropyl alcohol. This means 70 mL of isopropyl alcohol is present in every 100 mL of solution.

To find the volume of isopropyl alcohol in 500 mL solution:
Volume of alcohol=0.70×500=350mL\text{Volume of alcohol} = 0.70 \times 500 = 350 \, \text{mL}

Correct Answer: b. 350 mL


Problem 3: Concentration of KCl in the solution

The formula for percent concentration (% m/vm/v) is:
%(m/v)=Mass of solute (g)Volume of solution (mL)×100\% (m/v) = \frac{\text{Mass of solute (g)}}{\text{Volume of solution (mL)}} \times 100 Substituting the given values:
%(m/v)=15.0600.0×100=2.50%\% (m/v) = \frac{15.0}{600.0} \times 100 = 2.50\%

Correct Answer: d. 2.50%


Problem 4: Volume of 0.250 M KOH solution needed to contain 6.31 g of KOH

First, calculate the number of moles of KOH using its molar mass (KOH = 39.1 + 16 + 1 = 56.1 g/mol):
Moles of KOH=Mass of KOHMolar mass of KOH=6.3156.10.1125mol\text{Moles of KOH} = \frac{\text{Mass of KOH}}{\text{Molar mass of KOH}} = \frac{6.31}{56.1} \approx 0.1125 \, \text{mol}

Now, use the molarity equation to find the volume:
M=moles of solutevolume of solution in liters    Volume (L)=molesMM = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \implies \text{Volume (L)} = \frac{\text{moles}}{M} Substituting:
Volume (L)=0.11250.250=0.450L=450mL\text{Volume (L)} = \frac{0.1125}{0.250} = 0.450 \, \text{L} = 450 \, \text{mL}

Correct Answer: c. 450 mL


Final Answers:

  1. d. 14.0 g
  2. b. 350 mL
  3. d. 2.50%
  4. c. 450 mL

Would you like detailed explanations or have any questions?
Here are five related problems you might find helpful:

  1. If a necklace weighs 20 g, how much silver is present at 93.5% purity?
  2. What volume of water is needed to dilute 70 mL of rubbing alcohol to a 35% solution?
  3. Find the % concentration (m/v) of 10 g sugar in 200 mL solution.
  4. How many grams of KOH are needed to prepare 1 L of a 0.5 M solution?
  5. A 15 g alloy contains 80% copper. What is the mass of copper?

Tip: Always verify unit conversions and formulas to avoid errors in calculations.

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Math Problem Analysis

Mathematical Concepts

Percentage calculation
Concentration in solutions
Molarity and moles
Mass-to-volume conversions

Formulas

Mass of silver = Percentage × Total mass
Volume of solute = Percentage × Total volume
% (m/v) = (Mass of solute / Volume of solution) × 100
M = moles of solute / volume of solution (in liters)

Theorems

Proportional reasoning in percentage
Definition of molarity

Suitable Grade Level

Grades 9-12