Math Problem Statement

Question 14 (1 point) A solution contains 20g of solute dissolved in 0.5 L of water. What is the percentage of this solution? A) 2% B) 4% C) 10% D) 20%

Question 15 (1 point) How many milliliters of a 3% solution can be made if 6 grams of solute are used? A) 100mL B) 200mL C) 400mL D) 600mL

Solution

Let's solve these questions step by step.

Question 14: What is the percentage of the solution?

We are given:

  • 20 grams of solute
  • 0.5 L of water (which is 500 mL since 1 L = 1000 mL)

The formula for calculating the percentage of a solution is:

Percentage=(mass of solutetotal mass of solution)×100\text{Percentage} = \left( \frac{\text{mass of solute}}{\text{total mass of solution}} \right) \times 100

Total mass of the solution = mass of solute + mass of solvent (water). Since the density of water is approximately 1 g/mL, the mass of water is:

500mL=500grams500 \, \text{mL} = 500 \, \text{grams}

Now, calculate the total mass of the solution:

Total mass of solution=20g+500g=520g\text{Total mass of solution} = 20 \, \text{g} + 500 \, \text{g} = 520 \, \text{g}

Now calculate the percentage:

Percentage=(20520)×1003.85%\text{Percentage} = \left( \frac{20}{520} \right) \times 100 \approx 3.85\%

So, none of the provided answer choices exactly match, but based on approximation, the closest one would be 4%.

Question 15: How many milliliters of a 3% solution can be made with 6 grams of solute?

We are given:

  • 6 grams of solute
  • 3% solution

We can use the formula for percentage solutions:

Percentage=(mass of solutevolume of solution)×100\text{Percentage} = \left( \frac{\text{mass of solute}}{\text{volume of solution}} \right) \times 100

Rearranging to find the volume of solution:

Volume of solution=mass of solutePercentage×100=6g3\text{Volume of solution} = \frac{\text{mass of solute}}{\text{Percentage} \times 100} = \frac{6 \, \text{g}}{3}

Volume of solution=200mL\text{Volume of solution} = 200 \, \text{mL}

So, the correct answer is 200 mL.

Final Answers:

  • Question 14: B) 4%
  • Question 15: B) 200 mL

Would you like further details or clarifications on any step? Here are 5 related questions for you to explore:

  1. How would the result change if the density of water was different from 1 g/mL?
  2. What is the difference between mass percentage and volume percentage solutions?
  3. How do you calculate molarity and molality for a given solution?
  4. How can you determine the concentration of a solution from a titration experiment?
  5. What is the role of solute and solvent in determining the properties of a solution?

Tip: When calculating percentage solutions, always ensure you're consistent with your units (grams, milliliters, etc.), especially when working with water or other solvents.

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Math Problem Analysis

Mathematical Concepts

Percentage Calculations
Solution Concentration

Formulas

Percentage = (mass of solute / total mass of solution) × 100
Volume of solution = (mass of solute / (Percentage × 100))

Theorems

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Suitable Grade Level

Grades 8-10