Math Problem Statement
Let π and π be natural numbers such that π > π, π + π is divisible by 9, and π β π is divisible by 11. a) Determine the smallest possible value of the number π + π.
Solution
We are given two natural numbers and such that:
- ,
- is divisible by 9, i.e., ,
- is divisible by 11, i.e., .
We need to determine the smallest possible value of .
Step 1: Use the given conditions
Letβs denote:
From these two equations, we can solve for and by adding and subtracting:
Step 2: Solve for and
Add the two equations:
Now, subtract the second equation from the first:
Step 3: Ensure and are natural numbers
For both and to be natural numbers, the expressions and must be integers. This implies that and must both be even.
Step 4: Find the smallest value of
We now test values of and to find the smallest solution that satisfies the conditions.
For and : Thus, the smallest possible value of is .
Would you like more details or have any further questions?
Here are five related questions:
- How would you solve this problem if π β π were divisible by another number?
- What is the significance of using the system of equations method here?
- How can this approach be extended to other modular arithmetic problems?
- How does finding integer solutions relate to divisibility rules?
- Could we approach this problem geometrically in number theory?
Tip: When solving equations involving divisibility, express each term in modular form to find integer solutions efficiently.
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Math Problem Analysis
Mathematical Concepts
Number Theory
Modular Arithmetic
Systems of Linear Equations
Formulas
a + b β‘ 0 (mod 9)
a - b β‘ 0 (mod 11)
a = (9k + 11m) / 2
b = (9k - 11m) / 2
Theorems
Chinese Remainder Theorem
Divisibility Rules
Suitable Grade Level
Grades 10-12
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