Math Problem Statement
Solution
To determine the smallest number in the form that is divisible by , we need to understand the divisibility conditions:
- Divisibility by 72 means the number must be divisible by both 8 and 9.
- Divisibility by 8: The last three digits of the number must be divisible by .
- Divisibility by 9: The sum of all the digits must be divisible by .
Step-by-Step Solution:
-
Given format:
Here, are digits (0–9). -
Condition 1: Divisibility by 8
- Focus on the last three digits . To satisfy divisibility by 8, must be divisible by 8.
-
Condition 2: Divisibility by 9
- The sum of the digits must be divisible by .
Steps to Find the Smallest Number:
- Assume to minimize the number.
Then the number becomes , which is effectively . - Test small values for such that:
- is divisible by , and
- The sum is divisible by .
Testing:
- Start with small values for :
- :
- (divisible by 8).
- Sum of digits (not divisible by 9).
- :
- (divisible by 8).
- Sum of digits (not divisible by 9).
- :
- (divisible by 8).
- Sum of digits (not divisible by 9).
- :
- (divisible by 8).
- Sum of digits (divisible by 9).
- :
Final Answer:
The smallest number in the form that is divisible by is:
Let me know if you want further clarifications or additional examples!
Related Questions:
- How do you determine if a number is divisible by 8?
- How can you check for divisibility by 9?
- What is the general method to solve divisibility problems like this?
- Can this method be applied to larger numbers?
- How does the divisibility rule for 72 combine other rules?
Tip: Always start with conditions that restrict the form of the number, like divisibility rules, to simplify your search.
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Math Problem Analysis
Mathematical Concepts
Divisibility Rules
Number Theory
Formulas
Divisibility rule for 8: Last three digits divisible by 8
Divisibility rule for 9: Sum of all digits divisible by 9
Theorems
Combined divisibility rule for 72 (divisible by both 8 and 9)
Suitable Grade Level
Grades 8-10
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