Math Problem Statement

What is the smallest number in the form x123yzt that is divisible by 72?

Solution

To determine the smallest number in the form x123yztx123yzt that is divisible by 7272, we need to understand the divisibility conditions:

  1. Divisibility by 72 means the number must be divisible by both 8 and 9.
    • Divisibility by 8: The last three digits of the number must be divisible by 88.
    • Divisibility by 9: The sum of all the digits must be divisible by 99.

Step-by-Step Solution:

  1. Given format: x123yztx123yzt
    Here, x,y,z,tx, y, z, t are digits (0–9).

  2. Condition 1: Divisibility by 8

    • Focus on the last three digits yztyzt. To satisfy divisibility by 8, yztyzt must be divisible by 8.
  3. Condition 2: Divisibility by 9

    • The sum of the digits x+1+2+3+y+z+tx + 1 + 2 + 3 + y + z + t must be divisible by 99.

Steps to Find the Smallest Number:

  1. Assume x=0x = 0 to minimize the number.
    Then the number becomes 0123yzt0123yzt, which is effectively 123yzt123yzt.
  2. Test small values for yztyzt such that:
    • yztyzt is divisible by 88, and
    • The sum 1+2+3+y+z+t1 + 2 + 3 + y + z + t is divisible by 99.

Testing:

  • Start with small values for yztyzt:
    • yzt=024yzt = 024:
      • 024÷8=3024 \div 8 = 3 (divisible by 8).
      • Sum of digits 1+2+3+0+2+4=121 + 2 + 3 + 0 + 2 + 4 = 12 (not divisible by 9).
    • yzt=072yzt = 072:
      • 072÷8=9072 \div 8 = 9 (divisible by 8).
      • Sum of digits 1+2+3+0+7+2=151 + 2 + 3 + 0 + 7 + 2 = 15 (not divisible by 9).
    • yzt=144yzt = 144:
      • 144÷8=18144 \div 8 = 18 (divisible by 8).
      • Sum of digits 1+2+3+1+4+4=151 + 2 + 3 + 1 + 4 + 4 = 15 (not divisible by 9).
    • yzt=192yzt = 192:
      • 192÷8=24192 \div 8 = 24 (divisible by 8).
      • Sum of digits 1+2+3+1+9+2=181 + 2 + 3 + 1 + 9 + 2 = 18 (divisible by 9).

Final Answer:

The smallest number in the form x123yztx123yzt that is divisible by 7272 is:
123192\mathbf{123192}

Let me know if you want further clarifications or additional examples!


Related Questions:

  1. How do you determine if a number is divisible by 8?
  2. How can you check for divisibility by 9?
  3. What is the general method to solve divisibility problems like this?
  4. Can this method be applied to larger numbers?
  5. How does the divisibility rule for 72 combine other rules?

Tip: Always start with conditions that restrict the form of the number, like divisibility rules, to simplify your search.

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Math Problem Analysis

Mathematical Concepts

Divisibility Rules
Number Theory

Formulas

Divisibility rule for 8: Last three digits divisible by 8
Divisibility rule for 9: Sum of all digits divisible by 9

Theorems

Combined divisibility rule for 72 (divisible by both 8 and 9)

Suitable Grade Level

Grades 8-10