Math Problem Statement
The point P(6, 1) lies on the curve y =
x − 5 . (a) If Q is the point (x,
x − 5 ), use your calculator to find the slope of the secant line PQ (correct to six decimal places) for the following values of x. (i) 5.5
(ii) 5.9
(iii) 5.99
(iv) 5.999
(v) 6.5
(vi) 6.1
(vii) 6.01
(viii) 6.001
Solution
To find the slope of the secant line , we use the formula for the slope between two points and , which is:
Here, the point lies on the curve , meaning the y-coordinate of point P is .
For the point , the y-coordinate is given by . So, the formula for the slope becomes:
However, this is valid only when . At , we would need to compute a limit or approach the slope using values close to 6. This is why we compute the slope for various values of as you’ve requested.
Let’s now compute the slope for the given values of :
Values to compute:
Let me calculate the slopes for all these values.For all the given values of , the slope of the secant line is:
- For , the slope is
- For , the slope is
- For , the slope is
- For , the slope is
- For , the slope is
- For , the slope is
- For , the slope is
- For , the slope is
In this case, the slope is consistently 1.0 for all points near , indicating that the secant lines are almost horizontal.
Would you like more details on this, or do you have any other questions?
Here are 5 related questions:
- What happens to the slope as approaches 6?
- How can you determine the equation of a tangent line at ?
- Can you find the derivative of the function ?
- How would the slope change if the curve were more complex, such as ?
- How does this method extend to finding slopes of secant lines in 3D space?
Tip: The slope of a secant line between two points on a curve provides an average rate of change, while the derivative gives the instantaneous rate of change at a specific point.
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Math Problem Analysis
Mathematical Concepts
Algebra
Slopes of Secant Lines
Limits
Linear Equations
Formulas
Slope formula: (y2 - y1) / (x2 - x1)
For the curve y = x - 5, slope of PQ = (x - 6) / (x - 6)
Theorems
Slope of a Secant Line
Concept of Limits
Suitable Grade Level
Grades 10-12