Math Problem Statement

Let a>1 be some fixed number. Let h>0 be some small number. Write out a formula for the slope of the secant line to the graph of x=p(t) between the point at t=a and the point at t=a+h. You don't need to simplify this formula yet.

Solution

To find the slope of the secant line to the graph of x=p(t)x = p(t) between the points at t=at = a and t=a+ht = a + h, we use the formula for the slope between two points on a curve. The slope of a secant line is given by the difference in the function values divided by the difference in the independent variable.

The two points on the curve are:

  • At t=at = a: (a,p(a))\left(a, p(a)\right)
  • At t=a+ht = a + h: (a+h,p(a+h))\left(a + h, p(a + h)\right)

The slope of the secant line, msecantm_{\text{secant}}, is:

msecant=p(a+h)p(a)(a+h)am_{\text{secant}} = \frac{p(a + h) - p(a)}{(a + h) - a}

Since (a+h)a=h(a + h) - a = h, the formula simplifies to:

msecant=p(a+h)p(a)hm_{\text{secant}} = \frac{p(a + h) - p(a)}{h}

This is the unsimplified formula for the slope of the secant line between t=at = a and t=a+ht = a + h.

Would you like further explanation or examples?


Here are 5 related questions to extend this concept:

  1. How does the secant line relate to the derivative of the function at t=at = a?
  2. What happens to the slope of the secant line as hh approaches zero?
  3. How can you interpret the secant line geometrically in terms of the graph of p(t)p(t)?
  4. What is the formula for the tangent line's slope at t=at = a for the same function p(t)p(t)?
  5. How would the secant slope formula change if we consider the points t=at = a and t=bt = b instead of t=at = a and t=a+ht = a + h?

Tip: The secant line approximates the slope of the tangent line as hh becomes smaller. The derivative is the limit of the secant line's slope as hh approaches zero.

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Math Problem Analysis

Mathematical Concepts

Calculus
Secant Line
Limits

Formulas

m_sect = (p(a + h) - p(a)) / h

Theorems

Secant Line Slope Formula
Concept of Derivatives (as h → 0)

Suitable Grade Level

Grades 11-12, Early College