Math Problem Statement

Sketch a possible graph of a quadratic function which has two real roots (one positive, one negative), a graph that opens downwards, and y-intercept at (0, 4).

Solution

To sketch a graph of a quadratic function with the following conditions:

  1. Two real roots (one positive, one negative): This means the graph will intersect the x-axis at two points, one on the positive side and one on the negative side.
  2. Opens downwards: The parabola will have a downward shape, meaning the coefficient of the x2x^2 term in the quadratic equation is negative.
  3. Y-intercept at (0, 4): The graph crosses the y-axis at the point (0, 4).

Sketch description:

  • The graph is a parabola that opens downwards, starting high and curving down to intersect the x-axis at two points: one on the negative side and one on the positive side.
  • The vertex is the highest point, located between the two real roots.
  • The y-intercept at (0, 4) means the graph crosses the y-axis at 4, so when x=0x = 0, y=4y = 4.

Would you like me to generate a visual sketch of this graph?

Possible Relative Questions:

  1. What does the vertex of a quadratic function represent?
  2. How can we determine if a quadratic function has two real roots?
  3. What is the general form of a quadratic equation?
  4. How does the sign of the leading coefficient affect the direction of the parabola?
  5. How can you find the axis of symmetry for a quadratic graph?

Tip:

The y-intercept of a quadratic function is always the constant term in its standard form y=ax2+bx+cy = ax^2 + bx + c.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Graphing

Formulas

Standard form of quadratic equation: y = ax^2 + bx + c
Roots of a quadratic equation
Vertex formula: x = -b / 2a

Theorems

Quadratic formula
Properties of parabolas

Suitable Grade Level

Grades 9-10