Math Problem Statement

  1. Let f(x, y) = x 2 + y 2 . a) Sketch a contour plot for f, including labelled level curves at heights 9, 4, 1, 0 and −1. b) Sketch the level curves you drew in part (a) as they would appear in xyz-space as part of the graph of f. c) Based on the picture you drew in part (b), sketch a crude graph of f.

Solution

Let's solve this step by step.

Problem Breakdown:

Given the function f(x,y)=x2+y2f(x, y) = x^2 + y^2, this is the equation of a circle in terms of xx and yy, with the function representing the sum of squares.


Part (a): Contour Plot and Level Curves

  1. Contour Plot is a 2D plot where we fix different levels of f(x,y)f(x, y), i.e., we sketch circles of constant radius.
    • f(x,y)=x2+y2f(x, y) = x^2 + y^2 represents concentric circles in the xyxy-plane.
    • For different level values f(x,y)=cf(x, y) = c, we get circles with radius c\sqrt{c}.

Level Curves for Different Heights:

  • f(x,y)=9f(x, y) = 9x2+y2=9x^2 + y^2 = 9 → This is a circle of radius 3.
  • f(x,y)=4f(x, y) = 4x2+y2=4x^2 + y^2 = 4 → Circle of radius 2.
  • f(x,y)=1f(x, y) = 1x2+y2=1x^2 + y^2 = 1 → Circle of radius 1.
  • f(x,y)=0f(x, y) = 0x2+y2=0x^2 + y^2 = 0 → A single point at the origin (0,0).
  • f(x,y)=1f(x, y) = -1 → This is not possible, as x2+y20x^2 + y^2 \geq 0 (non-negative), so there is no level curve for 1-1.

The contour plot will consist of concentric circles centered at the origin with radii 3,2,13, 2, 1, and a point at the origin for the level curve f(x,y)=0f(x, y) = 0.

Part (b): Level Curves in XYZ-space

Now we translate the 2D contour plot into 3D space.

  • The level curves from part (a) (which are circles) will appear as horizontal cross-sections of the surface z=f(x,y)=x2+y2z = f(x, y) = x^2 + y^2.
  • Each horizontal slice corresponds to a particular height (zz), and for each height z=cz = c, the cross-section is a circle with radius c\sqrt{c}.

Thus, for:

  • z=9z = 9, you will see a circle with radius 3.
  • z=4z = 4, a circle with radius 2.
  • z=1z = 1, a circle with radius 1.
  • z=0z = 0, a single point (origin).
  • There is no level curve for z=1z = -1 because the function is always non-negative.

Part (c): Sketch of the Graph of f(x,y)f(x, y)

  • The function f(x,y)=x2+y2f(x, y) = x^2 + y^2 is a paraboloid.
  • The graph of ff is a surface that opens upwards from the origin in all directions.
  • The contour lines are horizontal cross-sections of this surface, with the radii of the cross-sections increasing as you go higher in zz.
  • The graph looks like a 3D bowl, where the base is at z=0z = 0 and expands outwards as zz increases.

Summary:

  • (a) The contour plot consists of concentric circles with radii 3,2,13, 2, 1, centered at the origin.
  • (b) In xyz-space, these circles correspond to horizontal cross-sections at different heights.
  • (c) The graph of f(x,y)=x2+y2f(x, y) = x^2 + y^2 is a paraboloid, with the surface opening upwards.

Would you like me to create or assist with the visual sketches? Or do you need further details?


Related Questions:

  1. What is the general shape of the graph of functions involving x2+y2x^2 + y^2?
  2. How would the contour plot change if the function were f(x,y)=x2y2f(x, y) = x^2 - y^2?
  3. What happens to the level curves if we change the function to f(x,y)=x2+y2f(x, y) = \sqrt{x^2 + y^2}?
  4. How can the contour plot be used to find the gradient of a function?
  5. What would the level curves look like for functions of the form f(x,y)=ax2+by2f(x, y) = ax^2 + by^2?

Tip:

The graph of f(x,y)=x2+y2f(x, y) = x^2 + y^2 can be related to cylindrical coordinates, where the distance from the origin on the xy-plane corresponds to the height in z.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Contour Plots
Paraboloids

Formulas

f(x, y) = x^2 + y^2
Radius of circle = sqrt(c)

Theorems

Properties of level curves for quadratic functions
Non-negativity of squared terms

Suitable Grade Level

Undergraduate Calculus (Grades 11-12 or College Level)