Math Problem Statement

vec a , vec b are two unit vectors inclined at pi/3 Then -[ vec a vec b + vec a * vec b vec b ] is

Solution

We are given two unit vectors a\vec{a} and b\vec{b}, inclined at an angle of θ=π3\theta = \frac{\pi}{3}. We are tasked with simplifying the following expression:

[a×b+(ab)b]-\left[ \vec{a} \times \vec{b} + \left( \vec{a} \cdot \vec{b} \right) \vec{b} \right]

Step-by-Step Breakdown:

1. Cross product (a×b\vec{a} \times \vec{b}):

The magnitude of the cross product of two vectors a\vec{a} and b\vec{b} is given by: a×b=absinθ|\vec{a} \times \vec{b}| = |\vec{a}| |\vec{b}| \sin\theta Since a\vec{a} and b\vec{b} are unit vectors, a=b=1|\vec{a}| = |\vec{b}| = 1, and θ=π3\theta = \frac{\pi}{3}, we get: a×b=11sin(π3)=sin(π3)=32|\vec{a} \times \vec{b}| = 1 \cdot 1 \cdot \sin\left(\frac{\pi}{3}\right) = \sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2} Thus, the cross product a×b\vec{a} \times \vec{b} has a magnitude of 32\frac{\sqrt{3}}{2} and is perpendicular to both a\vec{a} and b\vec{b}.

2. Dot product (ab\vec{a} \cdot \vec{b}):

The dot product of two vectors is given by: ab=abcosθ\vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos\theta Again, using a=b=1|\vec{a}| = |\vec{b}| = 1 and θ=π3\theta = \frac{\pi}{3}, we get: ab=11cos(π3)=cos(π3)=12\vec{a} \cdot \vec{b} = 1 \cdot 1 \cdot \cos\left(\frac{\pi}{3}\right) = \cos\left(\frac{\pi}{3}\right) = \frac{1}{2}

3. Expression Simplification:

We now substitute these results into the original expression:

[a×b+(ab)b]-\left[ \vec{a} \times \vec{b} + \left( \vec{a} \cdot \vec{b} \right) \vec{b} \right] This becomes: [a×b+12b]-\left[ \vec{a} \times \vec{b} + \frac{1}{2} \vec{b} \right]

Since a×b\vec{a} \times \vec{b} is perpendicular to b\vec{b}, we cannot directly combine these terms. Therefore, the simplified expression is:

(a×b+12b)-\left( \vec{a} \times \vec{b} + \frac{1}{2} \vec{b} \right)

Finally, distributing the negative sign:

a×b12b-\vec{a} \times \vec{b} - \frac{1}{2} \vec{b}

This is the simplified form of the given vector expression.


Would you like further details or have any questions?

Here are 5 related questions for practice:

  1. What is the geometric interpretation of a cross product?
  2. How do the cross product and dot product differ in vector operations?
  3. What are the properties of unit vectors?
  4. How does the angle between two vectors affect their cross product?
  5. What is the result of a cross product when two vectors are parallel?

Tip: Always remember that the cross product of two vectors results in a vector perpendicular to the plane containing the two original vectors!

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Math Problem Analysis

Mathematical Concepts

Vector Algebra
Unit Vectors
Dot Product
Cross Product
Angles Between Vectors

Formulas

Magnitude of cross product: |\vec{a} \times \vec{b}| = |\vec{a}| |\vec{b}| \sin(\theta)
Dot product: \vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos(\theta)

Theorems

Properties of Cross Product
Properties of Dot Product

Suitable Grade Level

Grades 11-12