Math Problem Statement

Sum[(40)Power[x,2],{i,1,20}]Divide[Sqrt[(40)9Power[x,4](41)],Power[x,8]]Surd[i,4]+(5i+5)

Solution

It seems like you're mixing some operations involving summation, powers, roots, and complex numbers. Let's break down and interpret the expression.

I'll rewrite your input into clearer mathematical notation:

[ \text{Sum}\left[ 40x^2 , {i, 1, 20}\right] \cdot \frac{\sqrt{9x^4}}{x^8} + \sqrt[4]{i} + (5i + 5) ]

Step-by-Step Breakdown:

  1. Summation: The first part seems to indicate a summation over a constant value 40x240x^2 from i=1i = 1 to i=20i = 20. Since the summation is over a constant term: i=12040x2=20×40x2=800x2\sum_{i=1}^{20} 40x^2 = 20 \times 40x^2 = 800x^2

  2. Simplifying the Fraction: The second part is 9x4x8\frac{\sqrt{9x^4}}{x^8}. 9x4=3x2\sqrt{9x^4} = 3x^2 So the fraction simplifies to: 3x2x8=3x6\frac{3x^2}{x^8} = \frac{3}{x^6}

  3. Fourth Root of ii: The next part is i4\sqrt[4]{i}, which refers to the fourth root of the imaginary unit ii. The fourth roots of ii are complex numbers, given by: i4=eiπ/8 or another equivalent form in polar coordinates.\sqrt[4]{i} = e^{i\pi/8} \text{ or another equivalent form in polar coordinates.}

  4. Expression 5i+55i + 5: This is a simple complex number, 5i+55i + 5, which can be written as 5(1+i)5(1 + i).

Putting It Together:

So, the entire expression becomes: 800x23x6+i4+5(1+i)800x^2 \cdot \frac{3}{x^6} + \sqrt[4]{i} + 5(1 + i) Simplifying the first part: 800x23x6=2400x4\frac{800x^2 \cdot 3}{x^6} = \frac{2400}{x^4}

Thus, the final expression is: 2400x4+i4+5(1+i)\frac{2400}{x^4} + \sqrt[4]{i} + 5(1 + i)

Further Details:

  1. The term i4\sqrt[4]{i} can be evaluated further for specific values if needed.
  2. The expression is simplified in terms of xx and involves both real and complex terms.

Do you want further details on the complex roots or more explanations?

Relative Questions:

  1. What are the fourth roots of any complex number, including ii?
  2. How do you simplify expressions involving powers of variables?
  3. Can the summation of a constant term be generalized for all constants?
  4. How are roots of imaginary numbers computed in polar form?
  5. What are the applications of summing polynomials?

Tip:

When simplifying complex expressions, always break them down into individual terms, working with one operation at a time!

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Math Problem Analysis

Mathematical Concepts

Summation
Powers of variables
Roots of complex numbers
Simplification of algebraic expressions

Formulas

Summation of a constant: \(\sum_{i=1}^{n} C = n \times C\)
Power and root simplification: \(\sqrt{9x^4} = 3x^2\)
Fourth root of a complex number: \(\sqrt[4]{i}\)

Theorems

Properties of exponents
Polar representation of complex numbers

Suitable Grade Level

Grades 10-12