This is a collection of complex number expressions that involve both real and imaginary numbers. Let's go through each one and simplify them.

1. $2 + \sqrt{-8}$:
   $\sqrt{-8} = \sqrt{8} \cdot i = 2\sqrt{2}i$, so: $2 + \sqrt{-8} = 2 + 2\sqrt{2}i$

2. $-\sqrt{-98}$:
   $\sqrt{-98} = \sqrt{98} \cdot i = 7\sqrt{2}i$, so: $-\sqrt{-98} = -7\sqrt{2}i$

3. $\sqrt{-216}$:
   $\sqrt{-216} = \sqrt{216} \cdot i = 6\sqrt{6}i$, so: $\sqrt{-216} = 6\sqrt{6}i$

4. $-\sqrt{-36}$:
   $\sqrt{-36} = 6i$, so: $-\sqrt{-36} = -6i$

5. $i \sqrt{-32}$:
   $\sqrt{-32} = \sqrt{32} \cdot i = 4\sqrt{2}i$, so: $i \sqrt{-32} = i \cdot 4\sqrt{2}i = -4\sqrt{2}$

6. $\sqrt{-128}$:
   $\sqrt{-128} = \sqrt{128} \cdot i = 8\sqrt{2}i$, so: $\sqrt{-128} = 8\sqrt{2}i$

7. $(3i)(-4i)(7i)$:
   Multiply the imaginary numbers: $(3i)(-4i)(7i) = (3 \cdot -4 \cdot 7) \cdot i^3 = -84 \cdot (-i) = 84i$

8. $(-3i) - (3i)$:
   $(-3i) - (3i) = -6i$

9. $(2i)(-8i)$:
   $(2i)(-8i) = -16i^2 = 16$

10. $(-4i) + (3i)$:
    $(-4i) + (3i) = -i$

11. $-8i \cdot 4i \cdot i$:
    $(-8i)(4i)(i) = -32i^3 = 32i$

12. $(8i)^2$:
    $(8i)^2 = 64i^2 = -64$

13. $i^{67}$:
    Since $i^4 = 1$, we use $i^{67} = i^{67 \mod 4} = i^3 = -i$.

14. $i^{45}$:
    $i^{45} = i^{45 \mod 4} = i$.

15. $i^{14}$:
    $i^{14} = i^{14 \mod 4} = i^2 = -1$.

16. $i^{39300}$:
    $i^{39300} = i^{39300 \mod 4} = i^0 = 1$.

17. $i^{8940}$:
    $i^{8940} = i^{8940 \mod 4} = i^0 = 1$.

18. $i^{50}$:
    $i^{50} = i^{50 \mod 4} = i^2 = -1$.

19. $(-4 - 7i) - (-6 + 4i)$:
    Subtract complex numbers: $(-4 - 7i) - (-6 + 4i) = (-4 + 6) + (-7i - 4i) = 2 - 11i$

20. $(-5 - 4i) + (-3 + 2i)$:
    $(-5 - 4i) + (-3 + 2i) = (-5 - 3) + (-4i + 2i) = -8 - 2i$

21. $(4 + 5i)(-7 - 2i) + (1 - 5i) - (-1 + 7i)$:
    First, multiply $(4 + 5i)(-7 - 2i)$: [ (4 + 5i)(-7 - 2i) = -28 -