Let's solve the expression:

$\sqrt{8} \times (2\sqrt{2} - 3\sqrt{3})$

Step 1: Simplify $\sqrt{8}$

We know that $\sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2}$.

So, the expression becomes:

$2\sqrt{2} \times (2\sqrt{2} - 3\sqrt{3})$

Step 2: Distribute $2\sqrt{2}$ across the terms in the parentheses

$2\sqrt{2} \times 2\sqrt{2} - 2\sqrt{2} \times 3\sqrt{3}$

Step 3: Simplify each term

1. $2\sqrt{2} \times 2\sqrt{2} = 4 \times 2 = 8$
2. $2\sqrt{2} \times 3\sqrt{3} = 6\sqrt{6}$

So, the expression simplifies to:

$8 - 6\sqrt{6}$

Thus, the simplified result is:

$\boxed{8 - 6\sqrt{6}}$

Would you like more details on the steps?

Here are 5 related questions you might find helpful:

1. How do you simplify square roots involving products like $\sqrt{8}$?
2. What is the distributive property in algebra, and how does it work with square roots?
3. How do you multiply two radical terms such as $\sqrt{2} \times \sqrt{2}$?
4. What is the difference between like and unlike radical terms?
5. Can radical expressions like this be further simplified in some cases?

Tip: Always simplify square roots before distributing or combining terms—it helps keep the calculations manageable!