Math Problem Statement

\left(\sqrt{10}+\sqrt{6}\right)\sqrt{8-2\sqrt{15}}

Solution

We need to simplify the expression:

(10+6)8215\left(\sqrt{10} + \sqrt{6}\right) \sqrt{8 - 2\sqrt{15}}

Step 1: Simplify the expression under the square root

We first focus on simplifying 8215\sqrt{8 - 2\sqrt{15}}. This expression is of the form a2b\sqrt{a - 2\sqrt{b}}, which can sometimes be expressed as:

a2b=xy\sqrt{a - 2\sqrt{b}} = \sqrt{x} - \sqrt{y}

To apply this, we need a=x+ya = x + y and b=xyb = xy.

Finding xx and yy:

  • Here a=8a = 8 and b=15b = 15.
  • We want to find xx and yy such that: x+y=8andxy=15x + y = 8 \quad \text{and} \quad xy = 15

These are the two equations we need to solve. Let’s solve them by factoring.

From the equation x+y=8x + y = 8 and xy=15xy = 15, xx and yy must be the solutions to the quadratic equation:

t2(x+y)t+xy=0t^2 - (x + y)t + xy = 0

Substituting x+y=8x + y = 8 and xy=15xy = 15, we get:

t28t+15=0t^2 - 8t + 15 = 0

Solving this quadratic equation using the quadratic formula:

t=(8)±(8)24(1)(15)2(1)t = \frac{-(-8) \pm \sqrt{(-8)^2 - 4(1)(15)}}{2(1)}

t=8±64602=8±42=8±22t = \frac{8 \pm \sqrt{64 - 60}}{2} = \frac{8 \pm \sqrt{4}}{2} = \frac{8 \pm 2}{2}

Thus, t=5t = 5 and t=3t = 3, so x=5x = 5 and y=3y = 3.

Step 2: Substitute and simplify

Now that we have x=5x = 5 and y=3y = 3, we can rewrite the square root as:

8215=53\sqrt{8 - 2\sqrt{15}} = \sqrt{5} - \sqrt{3}

Step 3: Expand the original expression

We now substitute this into the original expression:

(10+6)(53)\left(\sqrt{10} + \sqrt{6}\right)(\sqrt{5} - \sqrt{3})

Now, expand using the distributive property:

=105103+6563= \sqrt{10} \cdot \sqrt{5} - \sqrt{10} \cdot \sqrt{3} + \sqrt{6} \cdot \sqrt{5} - \sqrt{6} \cdot \sqrt{3}

Simplifying each term:

=5030+3018= \sqrt{50} - \sqrt{30} + \sqrt{30} - \sqrt{18}

=5218= 5\sqrt{2} - \sqrt{18}

Step 4: Simplify 18\sqrt{18}

We can simplify 18\sqrt{18} as:

18=9×2=32\sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2}

Step 5: Final simplification

Substitute this back:

5232=225\sqrt{2} - 3\sqrt{2} = 2\sqrt{2}

Thus, the simplified expression is:

22\boxed{2\sqrt{2}}

Let me know if you have any questions or if you would like further details!


Here are some related questions to practice:

  1. Simplify 12235\sqrt{12 - 2\sqrt{35}}.
  2. Expand (7+5)(3+2)(\sqrt{7} + \sqrt{5})(\sqrt{3} + \sqrt{2}).
  3. Solve 5+26\sqrt{5 + 2\sqrt{6}} in its simplified form.
  4. Simplify 6+28\sqrt{6 + 2\sqrt{8}}.
  5. Expand (86)(10+2)(\sqrt{8} - \sqrt{6})(\sqrt{10} + \sqrt{2}).

Tip: When simplifying expressions involving square roots, look for patterns of the form a±2b\sqrt{a \pm 2\sqrt{b}}, as they often simplify nicely.

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Math Problem Analysis

Mathematical Concepts

Algebra
Simplifying Radicals
Quadratic Equations

Formulas

Quadratic equation formula: ax^2 + bx + c = 0
Square root simplification: \sqrt{a - 2\sqrt{b}} = \sqrt{x} - \sqrt{y}
Distributive Property: (a + b)(c - d) = ac - ad + bc - bd

Theorems

Quadratic Formula: t = (-b \pm \sqrt{b^2 - 4ac}) / 2a

Suitable Grade Level

Grades 9-11