Math Problem Statement

3 StartRoot negative 16 EndRoot plus 6 StartRoot negative 4 EndRoot

Solution

Let's simplify the expression:
316+643 \sqrt{-16} + 6 \sqrt{-4}

  1. Simplifying 16\sqrt{-16} and 4\sqrt{-4}:
    We know that the square root of a negative number involves i, the imaginary unit, where i=1i = \sqrt{-1}.

    • 16=16×1=4i\sqrt{-16} = \sqrt{16} \times \sqrt{-1} = 4i
    • 4=4×1=2i\sqrt{-4} = \sqrt{4} \times \sqrt{-1} = 2i
  2. Now, substitute these back into the expression: 3(4i)+6(2i)=12i+12i3(4i) + 6(2i) = 12i + 12i

  3. Combine like terms: 12i+12i=24i12i + 12i = 24i

Thus, the simplified result is: 24i24i

Would you like further details on imaginary numbers or square roots of negative numbers? Here's a list of related questions:

  1. What is the imaginary unit ii and how is it used?
  2. Can you explain the difference between real and imaginary numbers?
  3. How do you simplify expressions involving 1\sqrt{-1}?
  4. What are complex numbers and how do they relate to imaginary numbers?
  5. How do you add and subtract imaginary numbers?

Tip: Imaginary numbers help represent quantities that cannot be expressed as real numbers, such as the square root of negative numbers.

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Math Problem Analysis

Mathematical Concepts

Imaginary Numbers
Square Roots
Complex Numbers

Formulas

√(-a) = i√a

Theorems

Imaginary Unit Theorem
Complex Number Addition

Suitable Grade Level

Grades 9-12