Math Problem Statement

Simplify the expression to a, plus, b, ia+bi form:

square root of, 16, end square root, minus, square root of, minus, 25, end square root, minus, square root of, 100, end square root, minus, square root of, minus, 100, end square root

16​−−25​−100​−−100​

Solution

We are given the expression:

1625100100\sqrt{16} - \sqrt{-25} - \sqrt{100} - \sqrt{-100}

Let's simplify this step by step:

1. Simplify 16\sqrt{16}:

16=4\sqrt{16} = 4

2. Simplify 25\sqrt{-25}:

Since we are taking the square root of a negative number, we will have an imaginary number. Recall that 1=i\sqrt{-1} = i, so: 25=251=5i\sqrt{-25} = \sqrt{25} \cdot \sqrt{-1} = 5i

3. Simplify 100\sqrt{100}:

100=10\sqrt{100} = 10

4. Simplify 100\sqrt{-100}:

Similarly, for the square root of 100-100, we get: 100=1001=10i\sqrt{-100} = \sqrt{100} \cdot \sqrt{-1} = 10i

Now, putting it all together:

45i1010i4 - 5i - 10 - 10i

Combine like terms:

  • Real part: 410=64 - 10 = -6
  • Imaginary part: 5i10i=15i-5i - 10i = -15i

So, the expression simplifies to: 615i-6 - 15i

This is in the form a+bia + bi, where a=6a = -6 and b=15b = -15.

Would you like any further details or clarifications?

Here are some related questions to help you dive deeper:

  1. What is the concept of imaginary numbers and why do we use ii?
  2. How can you simplify square roots of negative numbers in general?
  3. What are the basic operations with complex numbers (addition, subtraction)?
  4. How can you express a complex number in polar form?
  5. What happens when you multiply or divide complex numbers?

Tip: When dealing with the square root of a negative number, always remember to factor out the imaginary unit ii.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Square Roots
Imaginary Numbers

Formulas

√a = b for real numbers
√(-a) = bi for a > 0

Theorems

Imaginary Unit i (i = √(-1))

Suitable Grade Level

Grades 9-11