Math Problem Statement

RECTANGULAR FORM: a+bi ( $\sqrt{81}$ - $\sqrt{-36}$ )-( $\sqrt{-25}$ + $\sqrt{16}$ )

Solution

Let's break down the expression:

(8136)(25+16)\left( \sqrt{81} - \sqrt{-36} \right) - \left( \sqrt{-25} + \sqrt{16} \right)

Step 1: Simplifying each term

  1. 81=9\sqrt{81} = 9
  2. 36=6i\sqrt{-36} = 6i (since 1=i\sqrt{-1} = i, and 36=6\sqrt{36} = 6)
  3. 25=5i\sqrt{-25} = 5i (since 1=i\sqrt{-1} = i, and 25=5\sqrt{25} = 5)
  4. 16=4\sqrt{16} = 4

Step 2: Substitute these values into the expression

(96i)(5i+4)(9 - 6i) - (5i + 4)

Step 3: Simplifying the expression

Now, distribute the negative sign:

96i5i49 - 6i - 5i - 4

Combine like terms:

  1. Real parts: 94=59 - 4 = 5
  2. Imaginary parts: 6i5i=11i-6i - 5i = -11i

Thus, the simplified expression in rectangular form is:

511i5 - 11i

Final Answer:

The rectangular form is 511i5 - 11i.

Would you like further details or clarifications?

Here are 5 related questions you might find interesting:

  1. How do you simplify square roots of negative numbers?
  2. What is the process for adding and subtracting complex numbers?
  3. How can complex numbers be plotted on the complex plane?
  4. How do you find the modulus of a complex number?
  5. What is the polar form of a complex number?

Tip:

When simplifying square roots of negative numbers, always remember to factor out ii (the imaginary unit), where 1=i\sqrt{-1} = i.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Square Roots
Imaginary Numbers

Formulas

√(a) = b
√(-a) = bi (where b is real and i is the imaginary unit)

Theorems

Properties of complex numbers
Simplifying square roots of negative numbers

Suitable Grade Level

Grades 9-12