Math Problem Statement

Simplify the expression to a, plus, b, ia+bi form:

minus, square root of, 49, end square root, minus, square root of, minus, 36, end square root, plus, square root of, 9, end square root, minus, square root of, minus, 100, end square root

−49​−−36​+9​−−100​

Solution

It looks like there's a math domain error, which happens because we cannot directly compute the square root of a negative number using real numbers. However, we can express the square roots of negative numbers using imaginary numbers.

To proceed:

  • 49=7\sqrt{49} = 7
  • 36=6i\sqrt{-36} = 6i (since 36=6\sqrt{36} = 6 and we introduce ii)
  • 9=3\sqrt{9} = 3
  • 100=10i\sqrt{-100} = 10i (since 100=10\sqrt{100} = 10)

Now, we can rewrite the expression as:

76i+310i-7 - 6i + 3 - 10i

Combining the real and imaginary parts:

(7+3)+(6i10i)=416i(-7 + 3) + (-6i - 10i) = -4 - 16i

Thus, the simplified form is 416i-4 - 16i.

Would you like more details or further explanation?

Here are 5 related questions to consider:

  1. How do imaginary numbers work?
  2. What are complex numbers?
  3. How do you multiply complex numbers?
  4. Can you solve quadratic equations with complex solutions?
  5. How can complex numbers be represented on a graph?

Tip: Imaginary numbers are useful in engineering and physics, especially for solving equations involving wave functions or oscillations.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Imaginary Numbers
Square Roots

Formulas

√(x) where x is a positive number
√(−x) = i√(x) where x is a positive number

Theorems

Square root of a negative number involves imaginary numbers
Combining real and imaginary parts of complex numbers

Suitable Grade Level

Grades 10-12